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Factorize the following expressions: a) 3x - 6y + 15xy b) x3 - xy2 c) 3a2(2x-y) + 12y - 24x d) x4 - 16x2 - 36

Mathematics

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Answers

6 parts
a

3(x - 2y + 5xy)

b

x(x-y)(x+y)

c

3(2x-y)(a-2)(a+2)

d

(x2−18)(x2+2)(x^2 - 18)(x^2 + 2)

e

3(x - 1)(x - 4)

f

x(10 - x)(10 + x)

Step-by-step solution

15 steps

Here are the factorizations for each expression:

Part a· 1 step

To factorize 3x−6y+15xy3x - 6y + 15xy, we find the greatest common factor (GCF) of the coefficients.

  1. Identify the GCF of 3, 6, and 15, which is 3.

    3x−6y+15xy=3(x−2y+5xy)3x - 6y + 15xy = 3(x - 2y + 5xy)

    The factored expression is 3(x−2y+5xy)\boxed{3(x - 2y + 5xy)}.

Part bx(x-y)(x+y)

To factorize x3−xy2x^3 - xy^2, we find the greatest common factor (GCF) of the terms.

  1. Identify the GCF, which is xx.

    x3−xy2=x(x2−y2)x^3 - xy^2 = x(x^2 - y^2)
  2. Recognize that x2−y2x^2 - y^2 is a difference of squares, which factors as (x−y)(x+y)(x-y)(x+y).

    x(x2−y2)=x(x−y)(x+y)x(x^2 - y^2) = x(x-y)(x+y)

    The factored expression is x(x−y)(x+y)\boxed{x(x-y)(x+y)}.

Part c3(2x-y)(a-2)(a+2)

To factorize 3a2(2x−y)+12y−24x3a^2(2x-y) + 12y - 24x, we first rearrange the last two terms to find a common factor.

  1. Factor out -12 from the last two terms.

    12y−24x=−12(2x−y)12y - 24x = -12(2x - y)
  2. Substitute this back into the original expression.

    3a2(2x−y)−12(2x−y)3a^2(2x-y) - 12(2x-y)
  3. Factor out the common binomial factor (2x−y)(2x-y).

    (2x−y)(3a2−12)(2x-y)(3a^2 - 12)
  4. Factor out the GCF from (3a2−12)(3a^2 - 12), which is 3.

    (2x−y)3(a2−4)(2x-y)3(a^2 - 4)
  5. Recognize that a2−4a^2 - 4 is a difference of squares, which factors as (a−2)(a+2)(a-2)(a+2).

    3(2x−y)(a−2)(a+2)3(2x-y)(a-2)(a+2)

    The factored expression is 3(2x−y)(a−2)(a+2)\boxed{3(2x-y)(a-2)(a+2)}.

Part d

(x2−18)(x2+2)(x^2 - 18)(x^2 + 2)

To factorize x4−16x2−36x^4 - 16x^2 - 36, we treat it as a quadratic in terms of x2x^2. Let u=x2u = x^2.

  1. Rewrite the expression in terms of uu.

    u2−16u−36u^2 - 16u - 36
  2. Factor the quadratic.

    We need two numbers that multiply to -36 and add to -16. These numbers are -18 and 2.

    (u−18)(u+2)(u - 18)(u + 2)
  3. Substitute x2x^2 back for uu.

    (x2−18)(x2+2)(x^2 - 18)(x^2 + 2)

    The factored expression is (x2−18)(x2+2)\boxed{(x^2 - 18)(x^2 + 2)}.

Part e3(x - 1)(x - 4)

To factorize 3x2−15x+123x^2 - 15x + 12, we first find the greatest common factor (GCF).

  1. Identify the GCF of 3, 15, and 12, which is 3.

    3(x2−5x+4)3(x^2 - 5x + 4)
  2. Factor the quadratic expression x2−5x+4x^2 - 5x + 4.

    We need two numbers that multiply to 4 and add to -5. These numbers are -1 and -4.

    3(x−1)(x−4)3(x - 1)(x - 4)

    The factored expression is 3(x−1)(x−4)\boxed{3(x - 1)(x - 4)}.

Part fx(10 - x)(10 + x)

To factorize 100x−x3100x - x^3, we first find the greatest common factor (GCF).

  1. Identify the GCF, which is xx.

    x(100−x2)x(100 - x^2)
  2. Recognize that 100−x2100 - x^2 is a difference of squares, which factors as (10−x)(10+x)(10-x)(10+x).

    x(10−x)(10+x)x(10 - x)(10 + x)

    The factored expression is x(10−x)(10+x)\boxed{x(10 - x)(10 + x)}.

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