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Figure 1 shows triangle PQR. Draw triangle after translation vector (6 over -4).

Mathematics

ScanSolve AI Answer

Answer

P’(5,0),Q’(7,−3),R’(2,−3)\text{P'}(5, 0), \text{Q'}(7, -3), \text{R'}(2, -3)

Step-by-step solution

4 steps
  1. Identify the coordinates of the vertices of triangle PQR.

    From the graph:

    • Point P is at (−1,4)(-1, 4).
    • Point Q is at (1,1)(1, 1).
    • Point R is at (−4,1)(-4, 1).
  2. Apply the translation vector (6−4)\begin{pmatrix} 6 \\ -4 \end{pmatrix} to each vertex.

    To translate a point (x,y)(x, y) by a vector (ab)\begin{pmatrix} a \\ b \end{pmatrix}, the new point is (x+a,y+b)(x+a, y+b).

    For P(−1,4)(-1, 4):

    P′=(−1+6,4−4)=(5,0)P' = (-1+6, 4-4) = (5, 0)

    For Q(1,1)(1, 1):

    Q′=(1+6,1−4)=(7,−3)Q' = (1+6, 1-4) = (7, -3)

    For R(−4,1)(-4, 1):

    R′=(−4+6,1−4)=(2,−3)R' = (-4+6, 1-4) = (2, -3)
  3. State the coordinates of the translated triangle P'Q'R'.

    The new coordinates are:

    • P'(5,0)(5, 0)
    • Q'(7,−3)(7, -3)
    • R'(2,−3)(2, -3)
  4. Draw the image triangle P'Q'R'.

    To draw the image, plot the points P'(5,0)(5, 0), Q'(7,−3)(7, -3), and R'(2,−3)(2, -3) on the same graph paper. Then, connect these three points with straight lines to form the translated triangle P'Q'R'.

    The coordinates of the translated triangle are:
    P’(5,0),Q’(7,−3),R’(2,−3)\text{P'}(5, 0), \text{Q'}(7, -3), \text{R'}(2, -3)

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