First, calculate the values for y₁ = 2x + 5:

Here is the completed table of values for the relations $y_1 = 2x + 5$ and $y_2 = 3 - 2x$:

First, calculate the values for $y_1 = 2x + 5$:

• For $x = -4$: $y_1 = 2(-4) + 5 = -8 + 5 = -3$
• For $x = -3$: $y_1 = 2(-3) + 5 = -6 + 5 = -1$
• For $x = -2$: $y_1 = 2(-2) + 5 = -4 + 5 = 1$
• For $x = -1$: $y_1 = 2(-1) + 5 = -2 + 5 = 3$
• For $x = 0$: $y_1 = 2(0) + 5 = 0 + 5 = 5$
• For $x = 1$: $y_1 = 2(1) + 5 = 2 + 5 = 7$
• For $x = 2$: $y_1 = 2(2) + 5 = 4 + 5 = 9$
• For $x = 3$: $y_1 = 2(3) + 5 = 6 + 5 = 11$

Next, calculate the values for $y_2 = 3 - 2x$:

• For $x = -4$: $y_2 = 3 - 2(-4) = 3 + 8 = 11$
• For $x = -3$: $y_2 = 3 - 2(-3) = 3 + 6 = 9$
• For $x = -2$: $y_2 = 3 - 2(-2) = 3 + 4 = 7$
• For $x = -1$: $y_2 = 3 - 2(-1) = 3 + 2 = 5$
• For $x = 0$: $y_2 = 3 - 2(0) = 3 - 0 = 3$
• For $x = 1$: $y_2 = 3 - 2(1) = 3 - 2 = 1$
• For $x = 2$: $y_2 = 3 - 2(2) = 3 - 4 = -1$
• For $x = 3$: $y_2 = 3 - 2(3) = 3 - 6 = -3$

Here is the completed table:

$x$	-4	-3	-2	-1	0	1	2	3
$y_1$	-3	-1	1	3	5	7	9	11
$y_2$	11	9	7	5	3	1	-1	-3

$$\text{Table completed as above}$$