First, calculate the values for y_1 = 2x + 5:
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ScanSolve AI Answer
Here is the completed table of values for the relations $y_1 = 2x + 5$ and $y_2 = 3 - 2x$:
First, calculate the values for $y_1 = 2x + 5$:
For $x = -4$: $y_1 = 2(-4) + 5 = -8 + 5 = -3$
For $x = -3$: $y_1 = 2(-3) + 5 = -6 + 5 = -1$
For $x = -2$: $y_1 = 2(-2) + 5 = -4 + 5 = 1$
For $x = -1$: $y_1 = 2(-1) + 5 = -2 + 5 = 3$
For $x = 0$: $y_1 = 2(0) + 5 = 0 + 5 = 5$
For $x = 1$: $y_1 = 2(1) + 5 = 2 + 5 = 7$
For $x = 2$: $y_1 = 2(2) + 5 = 4 + 5 = 9$
For $x = 3$: $y_1 = 2(3) + 5 = 6 + 5 = 11$
Next, calculate the values for $y_2 = 3 - 2x$:
For $x = -4$: $y_2 = 3 - 2(-4) = 3 + 8 = 11$
For $x = -3$: $y_2 = 3 - 2(-3) = 3 + 6 = 9$
For $x = -2$: $y_2 = 3 - 2(-2) = 3 + 4 = 7$
For $x = -1$: $y_2 = 3 - 2(-1) = 3 + 2 = 5$
For $x = 0$: $y_2 = 3 - 2(0) = 3 - 0 = 3$
For $x = 1$: $y_2 = 3 - 2(1) = 3 - 2 = 1$
For $x = 2$: $y_2 = 3 - 2(2) = 3 - 4 = -1$
For $x = 3$: $y_2 = 3 - 2(3) = 3 - 6 = -3$
Here is the completed table:
| $x$ | -4 | -3 | -2 | -1 | 0 | 1 | 2 | 3 |
|-----|----|----|----|----|---|---|---|---|
| $y_1$ | -3 | -1 | 1 | 3 | 5 | 7 | 9 | 11 |
| $y_2$ | 11 | 9 | 7 | 5 | 3 | 1 | -1 | -3 |
$$\boxed{\text{Table completed as above}}$$
