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Solve the following addition problems using properties of addition. Check if both sides of the equation are equal.

Mathematics

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Here are the solutions to the problems:

1. Add the following

a)

  1. Add the given numbers.

    304781+251423=556204304781 + 251423 = 556204

    The sum is 556204\boxed{\text{556204}}.

    b)

  2. Add the given numbers.

    512049+37188=549237512049 + 37188 = 549237

    The sum is 549237\boxed{\text{549237}}.

    c)

  3. Add the given numbers.

    422433+17197+3210=442840422433 + 17197 + 3210 = 442840

    The sum is 442840\boxed{\text{442840}}.

    d)

  4. Add the given numbers.

    909090+18245+70208=997543909090 + 18245 + 70208 = 997543

    The sum is 997543\boxed{\text{997543}}.

    2. Use properties of addition to determine, if both sides are equal or not. Put '=' or '≠\neq'

    a)

  5. Compare both sides of the equation.

    470775+382115=382115+470775470775 + 382115 \quad \boxed{=} \quad 382115 + 470775

    This demonstrates the commutative property of addition.
    The sides are =\boxed{=}.

    b)

  6. Compare both sides of the equation.

    (356+471149)+8201=356+(471149+8201)(356 + 471149) + 8201 \quad \boxed{=} \quad 356 + (471149 + 8201)

    This demonstrates the associative property of addition.
    The sides are =\boxed{=}.

    c)

  7. Compare both sides of the equation.

    559197+0=559197559197 + 0 \quad \boxed{=} \quad 559197

    This demonstrates the additive identity property.
    The sides are =\boxed{=}.

    d)

  8. Compare both sides of the equation.

    0+480079=4800790 + 480079 \quad \boxed{=} \quad 480079

    This demonstrates the additive identity property.
    The sides are =\boxed{=}.

    e)

  9. Compare both sides of the equation.

    1+480079≠4800701 + 480079 \quad \boxed{\neq} \quad 480070 480080≠480070480080 \neq 480070

    The sides are ≠\boxed{\neq}.

    3. Find the value of the following:

    a) 1000 more than 113972

  10. Add 1000 to 113972.

    113972+1000=114972113972 + 1000 = 114972

    The value is 114972\boxed{\text{114972}}.

    b) 10000 more than 590074

  11. Add 10000 to 590074.

    590074+10000=600074590074 + 10000 = 600074

    The value is 600074\boxed{\text{600074}}.

    c) 2000 more than 888888

  12. Add 2000 to 888888.

    888888+2000=890888888888 + 2000 = 890888

    The value is 890888\boxed{\text{890888}}.

    d) 30000 more than 99999

  13. Add 30000 to 99999.

    99999+30000=12999999999 + 30000 = 129999

    The value is 129999\boxed{\text{129999}}.

    4. Roger wants to buy a car. He has a budget of rupees thirty nine lakhs. There are two options as shown below. Which option is within his budget?

    Roger's budget is thirty nine lakhs, which is ₹ 39,00,000\text{₹ } 39,00,000.

    Option A:

  14. Calculate the total cost for Option A.

    Total Cost A=Price+Tax+Accessories\text{Total Cost A} = \text{Price} + \text{Tax} + \text{Accessories} Total Cost A=₹ 35,00,000+₹ 2,38,672+₹ 1,73,500\text{Total Cost A} = \text{₹ } 35,00,000 + \text{₹ } 2,38,672 + \text{₹ } 1,73,500 Total Cost A=₹ 39,12,172\text{Total Cost A} = \text{₹ } 39,12,172
  15. Compare Total Cost A with Roger's budget.

    ₹ 39,12,172>₹ 39,00,000\text{₹ } 39,12,172 > \text{₹ } 39,00,000

    Option A is over budget.

    Option B:

  16. Calculate the total cost for Option B.

    Total Cost B=Price+Tax+Accessories\text{Total Cost B} = \text{Price} + \text{Tax} + \text{Accessories} Total Cost B=₹ 34,72,250+₹ 2,56,400+₹ 1,71,350\text{Total Cost B} = \text{₹ } 34,72,250 + \text{₹ } 2,56,400 + \text{₹ } 1,71,350 Total Cost B=₹ 39,00,000\text{Total Cost B} = \text{₹ } 39,00,000
  17. Compare Total Cost B with Roger's budget.

    ₹ 39,00,000=₹ 39,00,000\text{₹ } 39,00,000 = \text{₹ } 39,00,000

    Option B is exactly within budget.

    Roger's budget is ₹ 39,00,000\text{₹ } 39,00,000.
    Option A total cost: ₹ 39,12,172\text{₹ } 39,12,172.
    Option B total cost: ₹ 39,00,000\text{₹ } 39,00,000.

    Therefore, Option B\boxed{\text{Option B}} is within his budget.

    5. Nancy booked a two bedroom flat for rupees forty five lakh. There is an increase of rupees two lakh and forty thousand. What is the new price after increase? Is it more than ₹ 50,00,000\text{₹ } 50,00,000?

  18. Identify the initial price and the increase.

    Initial price = ₹ 45,00,000\text{₹ } 45,00,000
    Increase = ₹ 2,40,000\text{₹ } 2,40,000

  19. Calculate the new price after the increase.

    New Price=Initial Price+Increase\text{New Price} = \text{Initial Price} + \text{Increase} New Price=₹ 45,00,000+₹ 2,40,000\text{New Price} = \text{₹ } 45,00,000 + \text{₹ } 2,40,000 New Price=₹ 47,40,000\text{New Price} = \text{₹ } 47,40,000

    The new price after the increase is ₹ 47,40,000\boxed{\text{₹ } 47,40,000}.

  20. Compare the new price with ₹ 50,00,000\text{₹ } 50,00,000.

    ₹ 47,40,000<₹ 50,00,000\text{₹ } 47,40,000 < \text{₹ } 50,00,000

    The new price is not more than ₹ 50,00,000\text{₹ } 50,00,000.

    So, the new price is ₹ 47,40,000\text{₹ } 47,40,000, and it is not more than ₹ 50,00,000\boxed{\text{not more than } \text{₹ } 50,00,000}.

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