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Solve the following algebraic equations and inequalities: 1. 2x + 3 = 4x 2. 2a + 3 = 7x − 6 3. 6x − 5 < 8x 4. (3x+5)/2 >= (6x+1)/2

Mathematics

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Here are the solutions to the problems, with detailed steps:

:

2x+3=4x2x + 3 = 4x
  1. Subtract 2x2x from both sides of the equation to gather xx terms on one side.

    3=4x−2x3 = 4x - 2x
  2. Combine the xx terms.

    3=2x3 = 2x
  3. Divide both sides by 2 to solve for xx.

    32=2x2\frac{3}{2} = \frac{2x}{2} x=32x = \frac{3}{2}

    Your solution for this problem is correct.

    x=32\boxed{x = \frac{3}{2}}

    :

    2a+3=7x−62a + 3 = 7x - 6
  4. Add 6 to both sides of the equation to isolate the term containing xx.

    2a+3+6=7x2a + 3 + 6 = 7x 2a+9=7x2a + 9 = 7x
  5. Divide both sides by 7 to solve for xx.

    2a+97=7x7\frac{2a + 9}{7} = \frac{7x}{7} x=2a+97x = \frac{2a + 9}{7} x=2a+97\boxed{x = \frac{2a + 9}{7}}

    :

    6x−5<8x6x - 5 < 8x
  6. Subtract 8x8x from both sides of the inequality to gather xx terms on the left.

    6x−8x−5<06x - 8x - 5 < 0 −2x−5<0-2x - 5 < 0
  7. Add 5 to both sides to move the constant term to the right.

    −2x<5-2x < 5
  8. Divide both sides by −2-2.

    When dividing an inequality by a negative number, you must flip the direction of the inequality sign.

    −2x−2>5−2\frac{-2x}{-2} > \frac{5}{-2} x>−52x > -\frac{5}{2} x>−52\boxed{x > -\frac{5}{2}}

    :

    3x+52≥6x+12\frac{3x+5}{2} \ge \frac{6x+1}{2}
  9. Multiply both sides of the inequality by 2 to eliminate the denominators.

    2×(3x+52)≥2×(6x+12)2 \times \left(\frac{3x+5}{2}\right) \ge 2 \times \left(\frac{6x+1}{2}\right) 3x+5≥6x+13x+5 \ge 6x+1
  10. Subtract 6x6x from both sides to gather xx terms on the left.

    3x−6x+5≥13x - 6x + 5 \ge 1 −3x+5≥1-3x + 5 \ge 1
  11. Subtract 5 from both sides to move the constant term to the right.

    −3x≥1−5-3x \ge 1 - 5 −3x≥−4-3x \ge -4
  12. Divide both sides by −3-3.

    Remember to flip the inequality sign because you are dividing by a negative number.

    −3x−3≤−4−3\frac{-3x}{-3} \le \frac{-4}{-3} x≤43x \le \frac{4}{3} x≤43\boxed{x \le \frac{4}{3}}
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