Solve the following inequalities: 1) 3x < 6 2) −2x − 1 imes 5

Here are the solutions for the given inequalities. 1) Solve 3x < 6: Step 1: Divide both sides by 3. 3x/3 < 6/3 x < 2 The solution in interval notation is (−∞, 2). The solution is x < 2. 2) Solve −2x − 1 ≥ 5: Step 1: Add 1 to both sides of the inequality. −2x − 1 + 1 ≥ 5 + 1 −2x ≥ 6 Step 2: Divide both sides by −2. Remember to reverse the inequality sign when dividing by a negative number. (−2x)/(−2) ≤ (6)/(−2) x ≤ −3 The solution in interval notation is (−∞, −3]. The solution is x ≤ −3.

Solve the following inequalities: 1) 3x < 6 2) −2x − 1 imes 5

Here are the solutions for the given inequalities. 1) Solve 3x < 6: Step 1: Divide both sides by 3. 3x/3 < 6/3 x < 2 The solution in interval notation is (−∞, 2). The solution is x < 2. 2) Solve −2x − 1 ≥ 5: Step 1: Add 1 to both sides of the inequality. −2x − 1 + 1 ≥ 5 + 1 −2x ≥ 6 Step 2: Divide both sides by −2. Remember to reverse the inequality sign when dividing by a negative number. (−2x)/(−2) ≤ (6)/(−2) x ≤ −3 The solution in interval notation is (−∞, −3]. The solution is x ≤ −3.

Solved: Solve the following inequalities: 1) 3x < 6 2) −2x…

Here are the solutions for the given inequalities.

1) Solve $3x < 6$ :

Divide both sides by 3.
$\frac{3x}{3} < \frac{6}{3}$ $x < 2$
The solution in interval notation is $(-\infty, 2)$ .

The solution is $\boxed{x < 2}$ .

2) Solve $-2x - 1 \geq 5$ :
Add 1 to both sides of the inequality.
$-2x - 1 + 1 \geq 5 + 1$ $-2x \geq 6$
Divide both sides by $-2$ .
Remember to reverse the inequality sign when dividing by a negative number.
$\frac{-2x}{-2} \leq \frac{6}{-2}$ $x \leq -3$
The solution in interval notation is $(-\infty, -3]$ .

The solution is $\boxed{x \leq -3}$ .

Solve the following inequalities: 1) 3x < 6 2) -2x - 1 imes 5

Step-by-step solution

Divide both sides by 3.

Add 1 to both sides of the inequality.

Divide both sides by $-2$ .

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