Solve and graph the following inequalities: 1) 3x < 6 2) -2x - 1 >= 5

$$\frac{3x}{3} < \frac{6}{3}$$ $$x < 2$$

The solution is $\boxed{x < 2}$.

To represent this solution on a number line, draw a number line. Place an open circle at 2 (because $x$ is strictly less than 2, not equal to 2). Then, draw a line extending from the open circle to the left, indicating all numbers less than 2.

2) Solve $-2x - 1 \geq 5$:

$$-2x - 1 + 1 \geq 5 + 1$$ $$-2x \geq 6$$

Remember to reverse the inequality sign when dividing by a negative number.

$$\frac{-2x}{-2} \leq \frac{6}{-2}$$ $$x \leq -3$$

The solution is $\boxed{x \leq -3}$.

To represent this solution on a number line, draw a number line. Place a closed circle (or a filled dot) at $-3$ (because $x$ is less than or equal to $-3$). Then, draw a line extending from the closed circle to the left, indicating all numbers less than or equal to $-3$.