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Solve the following equations: 1. 3a = 10 + 9 2. 12 − 3m = 2m − 3 3. 3 + (1)/(2)x = 2(1)/(4)x - 1

Mathematics

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Here are the solutions to the equations:

1. 3a=10+93a = 10 + 9

  1. Simplify the right side of the equation.

    3a=193a = 19
  2. Divide both sides by 3 to solve for aa.

    a=193a = \frac{19}{3} a=193\boxed{a = \frac{19}{3}}

    2. 12−3m=2m−312 - 3m = 2m - 3

  3. Add $3m$ to both sides of the equation.

    12=2m+3m−312 = 2m + 3m - 3 12=5m−312 = 5m - 3
  4. Add 3 to both sides of the equation.

    12+3=5m12 + 3 = 5m 15=5m15 = 5m
  5. Divide both sides by 5 to solve for mm.

    155=m\frac{15}{5} = m 3=m3 = m m=3\boxed{m = 3}

    3. 3+12x=214x−13 + \frac{1}{2}x = 2\frac{1}{4}x - 1

  6. Convert the mixed number to an improper fraction.

    214=2×4+14=942\frac{1}{4} = \frac{2 \times 4 + 1}{4} = \frac{9}{4}

    The equation becomes:

    3+12x=94x−13 + \frac{1}{2}x = \frac{9}{4}x - 1
  7. Subtract 12x\frac{1}{2}x from both sides of the equation.

    3=94x−12x−13 = \frac{9}{4}x - \frac{1}{2}x - 1 3=94x−24x−13 = \frac{9}{4}x - \frac{2}{4}x - 1 3=74x−13 = \frac{7}{4}x - 1
  8. Add 1 to both sides of the equation.

    3+1=74x3 + 1 = \frac{7}{4}x 4=74x4 = \frac{7}{4}x
  9. Multiply both sides by 47\frac{4}{7} to solve for xx.

    4×47=x4 \times \frac{4}{7} = x 167=x\frac{16}{7} = x x=167\boxed{x = \frac{16}{7}}
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