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Solve the following integrals: a) integral [7x3 + 2x + 1] \,dx b) integral [7x3 + 2x] \,dx c) integral [5x2 + x] \,dx

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4 parts
a

74x4+x2+x+C\frac{7}{4}x^4 + x^2 + x + C

b

74x4+x2+C\frac{7}{4}x^4 + x^2 + C

c

53x3+12x2+C\frac{5}{3}x^3 + \frac{1}{2}x^2 + C

d

2x4+2x+C2x^4 + 2x + C

Step-by-step solution

8 steps

Here are the solutions to the integrals:

Part a· 2 steps

For the integral ∫[7x3+2x+1] dx\int [7x^3 + 2x + 1] \,dx

  1. Apply the power rule for integration, ∫xn dx=xn+1n+1+C\int x^n \,dx = \frac{x^{n+1}}{n+1} + C, and the constant rule, ∫k dx=kx+C\int k \,dx = kx + C.

    ∫7x3 dx=7x3+13+1=7x44\int 7x^3 \,dx = 7 \frac{x^{3+1}}{3+1} = 7 \frac{x^4}{4} ∫2x dx=2x1+11+1=2x22=x2\int 2x \,dx = 2 \frac{x^{1+1}}{1+1} = 2 \frac{x^2}{2} = x^2 ∫1 dx=x\int 1 \,dx = x
  2. Combine the results and add the constant of integration, CC.

    ∫[7x3+2x+1] dx=74x4+x2+x+C\int [7x^3 + 2x + 1] \,dx = \frac{7}{4}x^4 + x^2 + x + C

    The final answer is 74x4+x2+x+C\boxed{\frac{7}{4}x^4 + x^2 + x + C}.

Part b

74x4+x2+C\frac{7}{4}x^4 + x^2 + C

For the integral ∫[7x3+2x] dx\int [7x^3 + 2x] \,dx

  1. Apply the power rule for integration to each term.

    ∫7x3 dx=7x3+13+1=7x44\int 7x^3 \,dx = 7 \frac{x^{3+1}}{3+1} = 7 \frac{x^4}{4} ∫2x dx=2x1+11+1=2x22=x2\int 2x \,dx = 2 \frac{x^{1+1}}{1+1} = 2 \frac{x^2}{2} = x^2
  2. Combine the results and add the constant of integration, CC.

    ∫[7x3+2x] dx=74x4+x2+C\int [7x^3 + 2x] \,dx = \frac{7}{4}x^4 + x^2 + C

    The final answer is 74x4+x2+C\boxed{\frac{7}{4}x^4 + x^2 + C}.

Part c

53x3+12x2+C\frac{5}{3}x^3 + \frac{1}{2}x^2 + C

For the integral ∫[5x2+x] dx\int [5x^2 + x] \,dx

  1. Apply the power rule for integration to each term.

    ∫5x2 dx=5x2+12+1=5x33\int 5x^2 \,dx = 5 \frac{x^{2+1}}{2+1} = 5 \frac{x^3}{3} ∫x dx=x1+11+1=x22\int x \,dx = \frac{x^{1+1}}{1+1} = \frac{x^2}{2}
  2. Combine the results and add the constant of integration, CC.

    ∫[5x2+x] dx=53x3+12x2+C\int [5x^2 + x] \,dx = \frac{5}{3}x^3 + \frac{1}{2}x^2 + C

    The final answer is 53x3+12x2+C\boxed{\frac{5}{3}x^3 + \frac{1}{2}x^2 + C}.

Part d

2x4+2x+C2x^4 + 2x + C

For the integral ∫[8x3+2] dx\int [8x^3 + 2] \,dx

  1. Apply the power rule and constant rule for integration to each term.

    ∫8x3 dx=8x3+13+1=8x44=2x4\int 8x^3 \,dx = 8 \frac{x^{3+1}}{3+1} = 8 \frac{x^4}{4} = 2x^4 ∫2 dx=2x\int 2 \,dx = 2x
  2. Combine the results and add the constant of integration, CC.

    ∫[8x3+2] dx=2x4+2x+C\int [8x^3 + 2] \,dx = 2x^4 + 2x + C

    The final answer is 2x4+2x+C\boxed{2x^4 + 2x + C}.

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