Solve the following logarithmic equation: log5(2^(x-1)) + log5 2 = log5(2^(x-1) + 17/2) - log5(2^x - 3)

Here are the solutions for each equation:

a) The equation is $\log_5(2^{x-1}) + \log_5 2 = \log_5\left(2^{x-1} + \frac{17}{2}\right) - \log_5(2^x - 3)$.

Step 1: Use the logarithm properties $\log_b M + \log_b N = \log_b (MN)$ and $\log_b M - \log_b N = \log_b \frac{M}{N}$.

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