Solve the logarithmic equation: \2(3x−1) = 5

The definition of a logarithm states that if $\log_b(a) = c$, then $b^c = a$.
Given the equation $\log_2(3x-1) = 5$, we have $b=2$, $a=3x-1$, and $c=5$.

$$2^5 = 3x-1$$

Add 1 to both sides of the equation:

$$32 + 1 = 3x$$ $$33 = 3x$$

$$\frac{33}{3} = x$$ $$x = 11$$

The value of $x$ is $\boxed{\text{11}}$.