Solve the following problems: 1. a) Mrs Lehola's bedroom carpet. b) Mrs Lehola's farmyard. 2. a) Volume of the box of biscuits. b) Volume of Mr Radebe's bathroom.

The length of the room is $5 \text{ m}$.
Area of a square = $\text{length}^2$

The cost is $\text{R}70$ per $\text{m}^2$.

Mrs Lehola needs to buy $\boxed{25 \text{ m}^2}$ of carpeting, and it will cost $\boxed{\text{R}1750}$.

1. b) Mrs Lehola's farmyard:

The farmyard is $600 \text{ m}$ long and $600 \text{ m}$ wide.
Area = length $\times$ width

The area of her farm is $\boxed{360000 \text{ m}^2}$.

2. a) Volume of the box of biscuits:

The box has a length of $10 \text{ cm}$, a breadth of $10 \text{ cm}$, and a height of $10 \text{ cm}$.
Volume = length $\times$ breadth $\times$ height

The volume of the box is $\boxed{1000 \text{ cm}^3}$.

2. b) Volume of Mr Radebe's bathroom:

A cubic bathroom has equal length, breadth, and height. The height is $3 \text{ m}$, so the length and breadth are also $3 \text{ m}$.

Volume of a cube = $\text{side}^3$

The volume of his bathroom is $\boxed{27 \text{ m}^3}$.

2. c) Length of the side of the toy dice:

The volume of the dice is $216 \text{ cm}^3$. Since it's a cube, its volume is $\text{side}^3$.

The length of the side of the dice is $\boxed{6 \text{ cm}}$.