Solve the following problems: 1. a) Mrs Lehola's bedroom carpet. b) Mrs Lehola's farmyard. 2. a) Volume of the box of biscuits. b) Volume of Mr Radebe's bathroom.

Fresh day Faith, let's solve. Here are the solutions to the problems: 1. a) Mrs Lehola's bedroom carpet: Step 1: Calculate the area of the square room. The length of the room is 5 m. Area of a square = length^2 Area = (5 m)^2 = 25 m^2 Step 2: Calculate the total cost of the carpeting. The cost is R70 per m^2. Total Cost = 25 m^2 × R70/m^2 = R1750 Mrs Lehola needs to buy 25 m^2 of carpeting, and it will cost R1750. 1. b) Mrs Lehola's farmyard: Step 1: Calculate the area of the farmyard. The farmyard is 600 m long and 600 m wide. Area = length × width Area = 600 m × 600 m = 360000 m^2 The area of her farm is 360000 m^2. 2. a) Volume of the box of biscuits: Step 1: Calculate the volume of the box. The box has a length of 10 cm, a breadth of 10 cm, and a height of 10 cm. Volume = length × breadth × height Volume = 10 cm × 10 cm × 10 cm = 1000 cm^3 The volume of the box is 1000 cm^3. 2. b) Volume of Mr Radebe's bathroom: Step 1: Determine the side length of the cubic bathroom. A cubic bathroom has equal length, breadth, and height. The height is 3 m, so the length and breadth are also 3 m. Step 2: Calculate the volume of the bathroom. Volume of a cube = side^3 Volume = (3 m)^3 = 3 m × 3 m × 3 m = 27 m^3 The volume of his bathroom is 27 m^3. 2. c) Length of the side of the toy dice: Step 1: Find the cube root of the volume. The volume of the dice is 216 cm^3. Since it's a cube, its volume is side^3. side^3 = 216 cm^3 side = [3]216 cm^3 side = 6 cm The length of the side of the dice is 6 cm. What's next?