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Solve the following problems: 1) The sum of two numbers exceeds their product by one. Their difference is equal to their product less five. Find the numbers. 2) Solve the inequalities: 3x - 1 > -4 and

Mathematics

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Step-by-step solution

16 steps

1)

  1. Set up the equations based on the given information.

    Let the two numbers be xx and yy.
    "The sum of two numbers exceeds their product by one":

    x+y=xy+1(1)x + y = xy + 1 \quad (1)

    "Their difference is equal to their product less five":

    x−y=xy−5(2)x - y = xy - 5 \quad (2)
  2. Solve the system of equations.

    Subtract equation (2) from equation (1):

    (x+y)−(x−y)=(xy+1)−(xy−5)(x + y) - (x - y) = (xy + 1) - (xy - 5) x+y−x+y=xy+1−xy+5x + y - x + y = xy + 1 - xy + 5 2y=62y = 6 y=3y = 3
  3. Substitute the value of yy into equation (1) to find xx.

    x+3=x(3)+1x + 3 = x(3) + 1 x+3=3x+1x + 3 = 3x + 1 3−1=3x−x3 - 1 = 3x - x 2=2x2 = 2x x=1x = 1
  4. State the two numbers.

    The two numbers are 1 and 3.

    1 and 3\boxed{1 \text{ and } 3}

    2)

  5. Solve the first inequality.

    3x−1>−43x - 1 > -4

    Add 1 to both sides:

    3x>−4+13x > -4 + 1 3x>−33x > -3

    Divide by 3:

    x>−1x > -1
  6. Solve the second inequality.

    The problem states 2x+1≤72x + 1 \le 7.
    Subtract 1 from both sides:

    2x≤7−12x \le 7 - 1 2x≤62x \le 6

    Divide by 2:

    x≤3x \le 3
  7. Combine the solutions.

    The values of xx must satisfy both x>−1x > -1 and x≤3x \le 3.
    This can be written as a compound inequality:

    −1<x≤3\boxed{-1 < x \le 3}

    3)

  8. Evaluate the numerator.

    −12÷(−3)×4−(−15)-12 \div (-3) \times 4 - (-15)

    Perform division first:

    4×4−(−15)4 \times 4 - (-15)

    Perform multiplication:

    16−(−15)16 - (-15)

    Simplify subtraction of a negative:

    16+15=3116 + 15 = 31
  9. Evaluate the denominator.

    −5×6÷2+(−5)-5 \times 6 \div 2 + (-5)

    Perform multiplication first:

    −30÷2+(−5)-30 \div 2 + (-5)

    Perform division:

    −15+(−5)-15 + (-5)

    Perform addition:

    −15−5=−20-15 - 5 = -20
  10. Form the fraction and simplify.

    31−20=−3120\frac{31}{-20} = -\frac{31}{20} −3120\boxed{-\frac{31}{20}}

    4)

  11. Evaluate the numerator.

    (−4)(−2)+(−12)−(+3)+−20+(+4)+−6(-4)(-2) + (-12) - (+3) + -20 + (+4) + -6

    Perform multiplication:

    8+(−12)−3−20+4−68 + (-12) - 3 - 20 + 4 - 6

    Combine terms:

    8−12−3−20+4−68 - 12 - 3 - 20 + 4 - 6 (8+4)−(12+3+20+6)(8 + 4) - (12 + 3 + 20 + 6) 12−4112 - 41 −29-29
  12. Evaluate the denominator.

    The denominator is given as −9−(15)46−(8+2)−3-9 - (15) \quad 46 - (8+2) - 3. This implies multiplication between the two parts.
    First part:

    −9−15=−24-9 - 15 = -24

    Second part:

    46−(8+2)−346 - (8+2) - 3 46−10−346 - 10 - 3 36−3=3336 - 3 = 33

    Multiply the two parts:

    (−24)×(33)=−792(-24) \times (33) = -792
  13. Form the fraction and simplify.

    −29−792=29792\frac{-29}{-792} = \frac{29}{792} 29792\boxed{\frac{29}{792}}

    5)

  14. Evaluate the numerator.

    −8−2+12×9−4×6-8 - 2 + 12 \times 9 - 4 \times 6

    Perform multiplications:

    −8−2+108−24-8 - 2 + 108 - 24

    Perform additions and subtractions from left to right:

    −10+108−24-10 + 108 - 24 98−2498 - 24 7474
  15. Evaluate the denominator.

    56−7×256 - 7 \times 2

    Perform multiplication:

    56−1456 - 14

    Perform subtraction:

    4242
  16. Form the fraction and simplify.

    7442\frac{74}{42}

    Divide both numerator and denominator by their greatest common divisor, which is 2:

    74÷242÷2=3721\frac{74 \div 2}{42 \div 2} = \frac{37}{21} 3721\boxed{\frac{37}{21}}
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