Solve the following problems: 3. Complete the following sequences: c) 9,5; 9,6; 9,7; ... up to 10,3 d) 3,31; 3,36; 3,41; 3,46; ... up to 3,66. 4. Write down three decimal numbers between 6,1 and 6,2.

Each term increases by 0,1.

9,5
9,6 ($9,5 + 0,1$)
9,7 ($9,6 + 0,1$)
9,8 ($9,7 + 0,1$)
9,9 ($9,8 + 0,1$)
10,0 ($9,9 + 0,1$)
10,1 ($10,0 + 0,1$)
10,2 ($10,1 + 0,1$)
10,3 ($10,2 + 0,1$)
The completed sequence is: $\boxed{9,5; 9,6; 9,7; 9,8; 9,9; 10,0; 10,1; 10,2; 10,3}$

Each term increases by 0,05.

3,31
3,36 ($3,31 + 0,05$)
3,41 ($3,36 + 0,05$)
3,46 ($3,41 + 0,05$)
3,51 ($3,46 + 0,05$)
3,56 ($3,51 + 0,05$)
3,61 ($3,56 + 0,05$)
3,66 ($3,61 + 0,05$)
The completed sequence is: $\boxed{3,31; 3,36; 3,41; 3,46; 3,51; 3,56; 3,61; 3,66}$

4. Write down three decimal numbers between 6,1 and 6,2.

For example: $\boxed{6,13; 6,15; 6,18}$ (Other valid answers include $6,11; 6,12; 6,14; 6,16; 6,17; 6,19$).

5. Look at the number line and write down the decimal numbers represented by the letters A to D.

The distance between 0 and 0,05 is divided into 5 equal segments.
The value of each segment is $\frac{0,05}{5} = 0,01$.

A is 3 segments from 0. So, $A = 3 \times 0,01 = 0,03$.
B is 2 segments from 0,05. So, $B = 0,05 + (2 \times 0,01) = 0,05 + 0,02 = 0,07$.
C is 1 segment from 0,1. So, $C = 0,1 + (1 \times 0,01) = 0,1 + 0,01 = 0,11$.
D is 4 segments from 0,1. So, $D = 0,1 + (4 \times 0,01) = 0,1 + 0,04 = 0,14$.
The decimal numbers are:
A: $\boxed{0,03}$
B: $\boxed{0,07}$
C: $\boxed{0,11}$
D: $\boxed{0,14}$