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Solve the following problems involving length. 1. A man bought 39m 60cm of ribbon and 22m 28cm the same day. What is the total ribbon bought? 2. A seamstress has 6m 40cm of cloth and needs 3m 25cm. Ho

Mathematics

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Answers

2 parts
a

30 cm, 20 cm, 30 cm, 20 cm\text{30 cm, 20 cm, 30 cm, 20 cm}

b

parallelogram\text{parallelogram}

23 m\text{23 m}

3 m 73 cm\text{3 m 73 cm}

Step-by-step solution

2 steps

Step 1: Solve .
A man bought 39m 60cm of ribbon and 22m 28cm the same day. To find the total ribbon bought, add the two lengths.

39 m 60 cm+22 m 28 cm39 \text{ m } 60 \text{ cm} + 22 \text{ m } 28 \text{ cm}

Add the meters: 39 m+22 m=61 m39 \text{ m} + 22 \text{ m} = 61 \text{ m}
Add the centimeters: 60 cm+28 cm=88 cm60 \text{ cm} + 28 \text{ cm} = 88 \text{ cm}
The total length is 61 m 88 cm61 \text{ m } 88 \text{ cm}.
The man bought 61 m 88 cm\boxed{\text{61 m 88 cm}} of ribbon.

Step 2: Solve .
A seamstress has 6m 40cm of cloth and needs 3m 25cm. To find the remaining cloth, subtract the needed amount from the total.

6 m 40 cm−3 m 25 cm6 \text{ m } 40 \text{ cm} - 3 \text{ m } 25 \text{ cm}

Subtract the meters: 6 m−3 m=3 m6 \text{ m} - 3 \text{ m} = 3 \text{ m}
Subtract the centimeters: 40 cm−25 cm=15 cm40 \text{ cm} - 25 \text{ cm} = 15 \text{ cm}
The remaining cloth is 3 m 15 cm3 \text{ m } 15 \text{ cm}.
The remaining cloth is 3 m 15 cm\boxed{\text{3 m 15 cm}}.

Step 3: Solve .
Deji has four pieces of string, each 5m 42cm long. To find the total length, multiply the length of one string by 4.
Convert 5m 42cm to centimeters: 5×100 cm+42 cm=500 cm+42 cm=542 cm5 \times 100 \text{ cm} + 42 \text{ cm} = 500 \text{ cm} + 42 \text{ cm} = 542 \text{ cm}.
Multiply by 4:

542 cm×4=2168 cm542 \text{ cm} \times 4 = 2168 \text{ cm}

Convert back to meters and centimeters: 2168 cm=21 m 68 cm2168 \text{ cm} = 21 \text{ m } 68 \text{ cm}.
The total length of the four strings is 21 m 68 cm\boxed{\text{21 m 68 cm}}.

Step 4: Solve .
Three pipes of 8m 34cm, 10m 53cm, and 12m 38cm are joined. To find the total length, add the lengths of the three pipes.
Convert all lengths to centimeters:
8 m 34 cm=834 cm8 \text{ m } 34 \text{ cm} = 834 \text{ cm}
10 m 53 cm=1053 cm10 \text{ m } 53 \text{ cm} = 1053 \text{ cm}
12 m 38 cm=1238 cm12 \text{ m } 38 \text{ cm} = 1238 \text{ cm}
Add the lengths:

834 cm+1053 cm+1238 cm=3125 cm834 \text{ cm} + 1053 \text{ cm} + 1238 \text{ cm} = 3125 \text{ cm}

Convert back to meters and centimeters: 3125 cm=31 m 25 cm3125 \text{ cm} = 31 \text{ m } 25 \text{ cm}.
The total length of the pipe is 31 m 25 cm\boxed{\text{31 m 25 cm}}.

Step 5: Solve .
Bola is 129cm tall and her brother is 58cm tall. To find the difference in their height, subtract the brother's height from Bola's height.

129 cm−58 cm=71 cm129 \text{ cm} - 58 \text{ cm} = 71 \text{ cm}

The difference in their height is 71 cm\boxed{\text{71 cm}}.

Step 6: Solve .
A toilet pipe is 24m 26cm long. Lekan cuts off 12m. To find the remaining length, subtract the cut piece from the original length.

24 m 26 cm−12 m24 \text{ m } 26 \text{ cm} - 12 \text{ m}

Subtract the meters: 24 m−12 m=12 m24 \text{ m} - 12 \text{ m} = 12 \text{ m}
The centimeters remain the same: 26 cm26 \text{ cm}
The length of the pipe now is 12 m 26 cm12 \text{ m } 26 \text{ cm}.
The length of the pipe now is 12 m 26 cm\boxed{\text{12 m 26 cm}}.

Step 7: Solve .
The lengths of the four sides of a quadrilateral are 30cm, 20cm, 30cm, and 20cm.

Part a

The lengths of the sides are already given.

The lengths of the sides are 30 cm, 20 cm, 30 cm, 20 cm\boxed{\text{30 cm, 20 cm, 30 cm, 20 cm}}.

Part b

parallelogram\text{parallelogram}

A quadrilateral with two pairs of equal opposite sides is a *parallelogram

The quadrilateral is a parallelogram\boxed{\text{parallelogram}}.

  1. Solve .

    A mango tree is 29m high and an orange tree is 6m high. To find the difference in height, subtract the height of the orange tree from the mango tree.

    29 m−6 m=23 m29 \text{ m} - 6 \text{ m} = 23 \text{ m}

    The difference in the height of the two trees is 23 m\boxed{\text{23 m}}.

  2. Solve .

    A rope 5m 15cm long is joined to another rope, and their total length is 8m 88cm. To find the length of the second rope, subtract the length of the first rope from the total length.
    Convert all lengths to centimeters:
    Total length: 8 m 88 cm=8×100 cm+88 cm=800 cm+88 cm=888 cm8 \text{ m } 88 \text{ cm} = 8 \times 100 \text{ cm} + 88 \text{ cm} = 800 \text{ cm} + 88 \text{ cm} = 888 \text{ cm}
    Length of first rope: 5 m 15 cm=5×100 cm+15 cm=500 cm+15 cm=515 cm5 \text{ m } 15 \text{ cm} = 5 \times 100 \text{ cm} + 15 \text{ cm} = 500 \text{ cm} + 15 \text{ cm} = 515 \text{ cm}
    Subtract to find the length of the second rope:

    888 cm−515 cm=373 cm888 \text{ cm} - 515 \text{ cm} = 373 \text{ cm}

    Convert back to meters and centimeters: 373 cm=3 m 73 cm373 \text{ cm} = 3 \text{ m } 73 \text{ cm}.
    The length of the second rope is 3 m 73 cm\boxed{\text{3 m 73 cm}}.

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