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Solve these subtraction problems involving meters and centimeters: 1. 48m 65cm - 12m 15cm 2. 120m 28cm - 85m 19cm 3. 28m 28cm - 18m 19cm

Mathematics

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Here are the solutions for the subtraction problems:

:

48 m 65 cm−12 m 15 cm\begin{align*} & \quad 48 \text{ m } 65 \text{ cm} \\ &- \quad 12 \text{ m } 15 \text{ cm} \\ \hline \end{align*}
  1. Subtract the centimeters.

    65 cm−15 cm=50 cm65 \text{ cm} - 15 \text{ cm} = 50 \text{ cm}
  2. Subtract the meters.

    48 m−12 m=36 m48 \text{ m} - 12 \text{ m} = 36 \text{ m}

    The result for the first problem is:

    36 m 50 cm\boxed{\text{36 m 50 cm}}

    :

    120 m 28 cm−85 m 19 cm\begin{align*} & \quad 120 \text{ m } 28 \text{ cm} \\ &- \quad 85 \text{ m } 19 \text{ cm} \\ \hline \end{align*}
  3. Subtract the centimeters.

    28 cm−19 cm=9 cm28 \text{ cm} - 19 \text{ cm} = 9 \text{ cm}
  4. Subtract the meters.

    120 m−85 m=35 m120 \text{ m} - 85 \text{ m} = 35 \text{ m}

    The result for the second problem is:

    35 m 9 cm\boxed{\text{35 m 9 cm}}

    :

    28 m 28 cm−18 m 19 cm\begin{align*} & \quad 28 \text{ m } 28 \text{ cm} \\ &- \quad 18 \text{ m } 19 \text{ cm} \\ \hline \end{align*}
  5. Subtract the centimeters.

    28 cm−19 cm=9 cm28 \text{ cm} - 19 \text{ cm} = 9 \text{ cm}
  6. Subtract the meters.

    28 m−18 m=10 m28 \text{ m} - 18 \text{ m} = 10 \text{ m}

    The result for the third problem is:

    10 m 9 cm\boxed{\text{10 m 9 cm}}
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