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Solve the following subtraction problems involving meters and centimeters.

Mathematics

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Here are the solutions for the subtraction problems:

:

19 m 22 cm−11 m 19 cm\begin{align*} & \quad 19 \text{ m } 22 \text{ cm} \\ &- \quad 11 \text{ m } 19 \text{ cm} \\ \hline \end{align*}
  1. Subtract the centimeters.

    22 cm−19 cm=3 cm22 \text{ cm} - 19 \text{ cm} = 3 \text{ cm}
  2. Subtract the meters.

    19 m−11 m=8 m19 \text{ m} - 11 \text{ m} = 8 \text{ m}

    The result for the first problem is:

    8 m 3 cm\boxed{\text{8 m 3 cm}}

    :

    74 m 90 cm−18 m 98 cm\begin{align*} & \quad 74 \text{ m } 90 \text{ cm} \\ &- \quad 18 \text{ m } 98 \text{ cm} \\ \hline \end{align*}
  3. Subtract the centimeters.

    Since 90 cm<98 cm90 \text{ cm} < 98 \text{ cm}, we need to borrow 1 m1 \text{ m} from 74 m74 \text{ m}.
    1 m=100 cm1 \text{ m} = 100 \text{ cm}.
    So, 74 m74 \text{ m} becomes 73 m73 \text{ m}, and 90 cm90 \text{ cm} becomes 90 cm+100 cm=190 cm90 \text{ cm} + 100 \text{ cm} = 190 \text{ cm}.

  4. Subtract the centimeters with the borrowed value.

    190 cm−98 cm=92 cm190 \text{ cm} - 98 \text{ cm} = 92 \text{ cm}
  5. Subtract the meters (remembering that 74 m74 \text{ m} became 73 m73 \text{ m}).

    73 m−18 m=55 m73 \text{ m} - 18 \text{ m} = 55 \text{ m}

    The result for the second problem is:

    55 m 92 cm\boxed{\text{55 m 92 cm}}
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