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Solve the following subtraction problems involving meters and centimeters: 1. 8 m 62 cm - 5 m 50 cm 2. 7 m 39 cm - 4 m 16 cm 3. 7 m 84 cm - 5 m 67 cm 4. 79 m 49 cm - 59 m 67 cm

Mathematics

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here are the solutions for the "Friday: Revision Exercise":

1. 8 m 62 cm−5 m 50 cm8 \text{ m } 62 \text{ cm} - 5 \text{ m } 50 \text{ cm}

  1. Subtract the centimeters.

    62 cm−50 cm=12 cm62 \text{ cm} - 50 \text{ cm} = 12 \text{ cm}
  2. Subtract the meters.

    8 m−5 m=3 m8 \text{ m} - 5 \text{ m} = 3 \text{ m}

    The result is 3 m 12 cm3 \text{ m } 12 \text{ cm}.
    The correct option is (a).

    (a) 3 m 12 cm\boxed{\text{(a) } 3 \text{ m } 12 \text{ cm}}

    2. 7 m 39 cm−4 m 16 cm7 \text{ m } 39 \text{ cm} - 4 \text{ m } 16 \text{ cm}

  3. Subtract the centimeters.

    39 cm−16 cm=23 cm39 \text{ cm} - 16 \text{ cm} = 23 \text{ cm}
  4. Subtract the meters.

    7 m−4 m=3 m7 \text{ m} - 4 \text{ m} = 3 \text{ m}

    The result is 3 m 23 cm3 \text{ m } 23 \text{ cm}.
    The correct option is (b).

    (b) 3 m 23 cm\boxed{\text{(b) } 3 \text{ m } 23 \text{ cm}}

    3. 7 m 84 cm−5 m 67 cm7 \text{ m } 84 \text{ cm} - 5 \text{ m } 67 \text{ cm}

  5. Subtract the centimeters.

    84 cm−67 cm=17 cm84 \text{ cm} - 67 \text{ cm} = 17 \text{ cm}
  6. Subtract the meters.

    7 m−5 m=2 m7 \text{ m} - 5 \text{ m} = 2 \text{ m}

    The result is 2 m 17 cm2 \text{ m } 17 \text{ cm}.
    The correct option is (b).

    (b) 2 m 17 cm\boxed{\text{(b) } 2 \text{ m } 17 \text{ cm}}

    4. 79 m 49 cm−59 m 67 cm79 \text{ m } 49 \text{ cm} - 59 \text{ m } 67 \text{ cm}

  7. Since 49 cm<67 cm49 \text{ cm} < 67 \text{ cm}, borrow 1 m1 \text{ m} (which is 100 cm100 \text{ cm}) from the meters.

    79 m becomes 78 m79 \text{ m} \text{ becomes } 78 \text{ m} 49 cm becomes 49 cm+100 cm=149 cm49 \text{ cm} \text{ becomes } 49 \text{ cm} + 100 \text{ cm} = 149 \text{ cm}
  8. Subtract the centimeters.

    149 cm−67 cm=82 cm149 \text{ cm} - 67 \text{ cm} = 82 \text{ cm}
  9. Subtract the meters.

    78 m−59 m=19 m78 \text{ m} - 59 \text{ m} = 19 \text{ m}

    The result is 19 m 82 cm19 \text{ m } 82 \text{ cm}.
    The correct option is (a).

    (a) 19 m 82 cm\boxed{\text{(a) } 19 \text{ m } 82 \text{ cm}}

    5. 2 m 96 cm−1 m 85 cm2 \text{ m } 96 \text{ cm} - 1 \text{ m } 85 \text{ cm}

  10. Subtract the centimeters.

    96 cm−85 cm=11 cm96 \text{ cm} - 85 \text{ cm} = 11 \text{ cm}
  11. Subtract the meters.

    2 m−1 m=1 m2 \text{ m} - 1 \text{ m} = 1 \text{ m}

    The result is 1 m 11 cm1 \text{ m } 11 \text{ cm}.
    The correct option is (b).

    (b) 1 m 11 cm\boxed{\text{(b) } 1 \text{ m } 11 \text{ cm}}

    6. A table 4 m 36 cm4 \text{ m } 36 \text{ cm} long is joined to another 2 m 75 cm2 \text{ m } 75 \text{ cm} long. What is the total length of the new table?

  12. Add the centimeters.

    36 cm+75 cm=111 cm36 \text{ cm} + 75 \text{ cm} = 111 \text{ cm}
  13. Convert 111 cm111 \text{ cm} to meters and centimeters.

    111 cm=1 m 11 cm111 \text{ cm} = 1 \text{ m } 11 \text{ cm}
  14. Add the meters, including the carry-over from centimeters.

    4 m+2 m+1 m=7 m4 \text{ m} + 2 \text{ m} + 1 \text{ m} = 7 \text{ m}

    The total length is 7 m 11 cm7 \text{ m } 11 \text{ cm}.
    The correct option is (a).

    (a) 7 m 11 cm\boxed{\text{(a) } 7 \text{ m } 11 \text{ cm}}

    7. 17 m 36 cm−9 m 24 cm17 \text{ m } 36 \text{ cm} - 9 \text{ m } 24 \text{ cm}

  15. Subtract the centimeters.

    36 cm−24 cm=12 cm36 \text{ cm} - 24 \text{ cm} = 12 \text{ cm}
  16. Subtract the meters.

    17 m−9 m=8 m17 \text{ m} - 9 \text{ m} = 8 \text{ m}

    The result is 8 m 12 cm8 \text{ m } 12 \text{ cm}.
    The correct option is (b).

    (b) 8 m 12 cm\boxed{\text{(b) } 8 \text{ m } 12 \text{ cm}}
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