Solve the following quadratic equations: a) (x-4)(x+7)=0, b) (2x)(x+8)=0, d) x2=37, e) 9x2=25, f) 4x2=4, h) x2=32, i) 20=x2+4

Fresh day Pretty, let's solve. Here are the solutions for the circled problems: a) Step 1: Set each factor equal to zero. x - 4 = 0 or x + 7 = 0 Step 2: Solve for x. x = 4 or x = -7 The solutions are x = 4, -7. b) Step 1: Set each factor equal to zero. 2x = 0 or x + 8 = 0 Step 2: Solve for x. x = 0 or x = -8 The solutions are x = 0, -8. d) Step 1: Add 12 to both sides of the equation. x^2 - 12 + 12 = 37 + 12 x^2 = 49 Step 2: Take the square root of both sides. x = ±sqrt(49) x = ± 7 The solutions are x = 7, -7. e) Step 1: Divide both sides by 9. (9x^2)/(9) = (25)/(9) x^2 = (25)/(9) Step 2: Take the square root of both sides. x = ±sqrt((25)/(9)) x = ±(5)/(3) The solutions are x = (5)/(3), -(5)/(3). f) Step 1: Divide both sides by 4. (4x^2)/(4) = (4)/(4) x^2 = 1 Step 2: Take the square root of both sides. x = ±sqrt(1) x = ± 1 The solutions are x = 1, -1. h) Step 1: Add 4 to both sides of the equation. x^2 - 4 + 4 = 32 + 4 x^2 = 36 Step 2: Take the square root of both sides. x = ±sqrt(36) x = ± 6 The solutions are x = 6, -6. i) Step 1: Subtract 4 from both sides of the equation. 20 - 4 = x^2 + 4 - 4 16 = x^2 Step 2: Take the square root of both sides. x = ±sqrt(16) x = ± 4 The solutions are x = 4, -4. j) Step 1: Subtract 2 from both sides of the equation. 5x^2 + 2 - 2 = 7 - 2 5x^2 = 5 Step 2: Divide both sides by 5. (5x^2)/(5) = (5)/(5) x^2 = 1 Step 3: Take the square root of both sides. x = ±sqrt(1) x = ± 1 The solutions are x = 1, -1. Send me the next one 📸