For an inclined plane, the relationship between the height (h) to which a load is raised, the length of the inclined plane (L, which is the distance moved by the effort), and the angle of inclinat

• Angle of inclination, $\theta = 45^\circ$.
• Height the load is moved, $h = 20 \text{ m}$.

We know that $\sin(45^\circ) = \frac{\sqrt{2}}{2} \approx 0.7071$.

The calculated distance is approximately $28.28 \text{ m}$. This matches option (A).

The final answer is $\text{A) } 28.28 \text{ m}$.