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For each equation, complete the table of values and draw its graph for values of x from -2 to 2. a) y = 3x + 3 b) y = x − 9

Mathematics

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Step-by-step solution

13 steps

Here are the completed tables of values for each equation. To draw the graphs, you would plot the coordinate pairs $(x, y)$ from each table and connect them with a straight line.

Part 3· 8 steps

For each equation, complete the table of values and draw its graph for values of xx from −2-2 to 2.

  • a) y=3x+3y = 3x + 3
  1. Substitute each xx value into the equation y=3x+3y = 3x + 3.

    For $x = -2$, $y = 3(-2) + 3 = -6 + 3 = -3$.  
    For $x = -1$, $y = 3(-1) + 3 = -3 + 3 = 0$.  
    For $x = 0$, $y = 3(0) + 3 = 0 + 3 = 3$.  
    For $x = 1$, $y = 3(1) + 3 = 3 + 3 = 6$.  
    For $x = 2$, $y = 3(2) + 3 = 6 + 3 = 9$.
    
  2. Complete the table.

    $$
    \begin{array}{|c|c|c|c|c|c|}
    \hline
    x & -2 & -1 & 0 & 1 & 2 \\
    \hline
    y & \textbf{-3} & \textbf{0} & \textbf{3} & \textbf{6} & \textbf{9} \\
    \hline
    \end{array}
    $$
    The points to plot are $(-2, -3)$, $(-1, 0)$, $(0, 3)$, $(1, 6)$, $(2, 9)$.
    
    • b) y=x−9y = x - 9
  3. Substitute each xx value into the equation y=x−9y = x - 9.

    For $x = -2$, $y = -2 - 9 = -11$.  
    For $x = -1$, $y = -1 - 9 = -10$.  
    For $x = 0$, $y = 0 - 9 = -9$.  
    For $x = 1$, $y = 1 - 9 = -8$.  
    For $x = 2$, $y = 2 - 9 = -7$.
    
  4. Complete the table.

    $$
    \begin{array}{|c|c|c|c|c|c|}
    \hline
    x & -2 & -1 & 0 & 1 & 2 \\
    \hline
    y & \textbf{-11} & \textbf{-10} & \textbf{-9} & \textbf{-8} & \textbf{-7} \\
    \hline
    \end{array}
    $$
    The points to plot are $(-2, -11)$, $(-1, -10)$, $(0, -9)$, $(1, -8)$, $(2, -7)$.
    
    • c) y=x−2y = x - 2
  5. Substitute each xx value into the equation y=x−2y = x - 2.

    For $x = -2$, $y = -2 - 2 = -4$.  
    For $x = -1$, $y = -1 - 2 = -3$.  
    For $x = 0$, $y = 0 - 2 = -2$.  
    For $x = 1$, $y = 1 - 2 = -1$.  
    For $x = 2$, $y = 2 - 2 = 0$.
    
  6. Complete the table.

    $$
    \begin{array}{|c|c|c|c|c|c|}
    \hline
    x & -2 & -1 & 0 & 1 & 2 \\
    \hline
    y & \textbf{-4} & \textbf{-3} & \textbf{-2} & \textbf{-1} & \textbf{0} \\
    \hline
    \end{array}
    $$
    The points to plot are $(-2, -4)$, $(-1, -3)$, $(0, -2)$, $(1, -1)$, $(2, 0)$.
    
    • d) y=xy = x
  7. Substitute each xx value into the equation y=xy = x.

    For $x = -2$, $y = -2$.  
    For $x = -1$, $y = -1$.  
    For $x = 0$, $y = 0$.  
    For $x = 1$, $y = 1$.  
    For $x = 2$, $y = 2$.
    
  8. Complete the table.

    $$
    \begin{array}{|c|c|c|c|c|c|}
    \hline
    x & -2 & -1 & 0 & 1 & 2 \\
    \hline
    y & \textbf{-2} & \textbf{-1} & \textbf{0} & \textbf{1} & \textbf{2} \\
    \hline
    \end{array}
    $$
    The points to plot are $(-2, -2)$, $(-1, -1)$, $(0, 0)$, $(1, 1)$, $(2, 2)$.
    

Part 4· 5 steps

For each equation, complete the table of values and draw its graph for values of xx from −2-2 to 4.

  • a) y=12x+1y = \frac{1}{2}x + 1
  1. Substitute each xx value into the equation y=12x+1y = \frac{1}{2}x + 1.

    For $x = -2$, $y = \frac{1}{2}(-2) + 1 = -1 + 1 = 0$.  
    For $x = -1$, $y = \frac{1}{2}(-1) + 1 = -0.5 + 1 = 0.5$.  
    For $x = 0$, $y = \frac{1}{2}(0) + 1 = 0 + 1 = 1$.  
    For $x = 1$, $y = \frac{1}{2}(1) + 1 = 0.5 + 1 = 1.5$.  
    For $x = 2$, $y = \frac{1}{2}(2) + 1 = 1 + 1 = 2$.  
    For $x = 3$, $y = \frac{1}{2}(3) + 1 = 1.5 + 1 = 2.5$.  
    For $x = 4$, $y = \frac{1}{2}(4) + 1 = 2 + 1 = 3$.
    
  2. Complete the table.

    $$
    \begin{array}{|c|c|c|c|c|c|c|c|}
    \hline
    x & -2 & -1 & 0 & 1 & 2 & 3 & 4 \\
    \hline
    y & \textbf{0} & \textbf{0.5} & \textbf{1} & \textbf{1.5} & \textbf{2} & \textbf{2.5} & \textbf{3} \\
    \hline
    \end{array}
    $$
    The points to plot are $(-2, 0)$, $(-1, 0.5)$, $(0, 1)$, $(1, 1.5)$, $(2, 2)$, $(3, 2.5)$, $(4, 3)$.
    
    • b) y=14x+5y = \frac{1}{4}x + 5
  3. Substitute each xx value into the equation y=14x+5y = \frac{1}{4}x + 5.

    For $x = -2$, $y = \frac{1}{4}(-2) + 5 = -0.5 + 5 = 4.5$.  
    For $x = -1$, $y = \frac{1}{4}(-1) + 5 = -0.25 + 5 = 4.75$.  
    For $x = 0$, $y = \frac{1}{4}(0) + 5 = 0 + 5 = 5$.  
    For $x = 1$, $y = \frac{1}{4}(1) + 5 = 0.25 + 5 = 5.25$.  
    For $x = 2$, $y = \frac{1}{4}(2) + 5 = 0.5 + 5 = 5.5$.  
    For $x = 3$, $y = \frac{1}{4}(3) + 5 = 0.75 + 5 = 5.75$.  
    For $x = 4$, $y = \frac{1}{4}(4) + 5 = 1 + 5 = 6$.
    
  4. Complete the table.

    $$
    \begin{array}{|c|c|c|c|c|c|c|c|}
    \hline
    x & -2 & -1 & 0 & 1 & 2 & 3 & 4 \\
    \hline
    y & \textbf{4.5} & \textbf{4.75} & \textbf{5} & \textbf{5.25} & \textbf{5.5} & \textbf{5.75} & \textbf{6} \\
    \hline
    \end{array}
    $$
    The points to plot are $(-2, 4.5)$, $(-1, 4.75)$, $(0, 5)$, $(1, 5.25)$, $(2, 5.5)$, $(3, 5.75)$, $(4, 6)$.
    
    • c) y=13x+1y = \frac{1}{3}x + 1
  5. Substitute each xx value into the equation y=13x+1y = \frac{1}{3}x + 1.

    For $x = -2$, $y = \frac{1}{3}(-2) + 1 = -\frac{2}{3} + 1 = \frac{1}{3}$.  
    For $x = -1$, $y = \frac{1}{3}(-1) + 1 = -\frac{1}{3} + 1 = \frac{2}{3}$.  
    For $x = 0$, $y = \frac{1}{3}(0) + 1 = 0 + 1 = 1$.  
    For $x = 1$, $y = \frac{1}{3}(1) + 1 = \frac{1}{3} + 1 = \frac{4}{3}$.  
    For $x = 2$, $y = \frac{1}{3}(2) + 1 = \frac{2}{3} + 1 = \frac{5}{3}$.  
    For $x = 3$, $y = \frac{1}{3}(3) + 1 = 1 + 1 = 2$.  
    For $x = 4$,
    
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