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For the sequence defined by Un+1 = 1 + (1)/(2) Un, find a formula for Un using the general method, expressing it in terms of U1.

Mathematics

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Here's how to solve parts (b) and (c) for the sequence defined by Un+1=1+12UnU_{n+1} = 1 + \frac{1}{2} U_n. We will express the formulas in terms of the initial term U1U_1, as it is not specified for this new recurrence relation.

b) Find a formula for UnU_n using the general method.

  1. Find the homogeneous solution.

    The homogeneous part of the recurrence relation is Un+1=12UnU_{n+1} = \frac{1}{2} U_n.
    The characteristic equation is r=12r = \frac{1}{2}.
    Thus, the homogeneous solution is Un(h)=A(12)nU_n^{(h)} = A \left(\frac{1}{2}\right)^n, where AA is a constant.

  2. Find the particular solution.

    Assume a constant particular solution Un(p)=CU_n^{(p)} = C. Substitute this into the original recurrence relation:

    C=1+12CC = 1 + \frac{1}{2} C C−12C=1C - \frac{1}{2} C = 1 12C=1\frac{1}{2} C = 1 C=2C = 2

    So, the particular solution is Un(p)=2U_n^{(p)} = 2.

  3. Combine to find the general solution.

    The general solution is the sum of the homogeneous and particular solutions:

    Un=Un(h)+Un(p)U_n = U_n^{(h)} + U_n^{(p)} Un=A(12)n+2U_n = A \left(\frac{1}{2}\right)^n + 2
  4. Determine the constant AA using the initial term U1U_1.

    For n=1n=1:

    U1=A(12)1+2U_1 = A \left(\frac{1}{2}\right)^1 + 2 U1=A2+2U_1 = \frac{A}{2} + 2 A2=U1−2\frac{A}{2} = U_1 - 2 A=2(U1−2)A = 2(U_1 - 2)
  5. Substitute AA back into the general

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