Solve for x if one angle is given as 2×+10° and a perpendicular. angle is 90°

Since the lines are perpendicular, all angles formed at the intersection are $90^\circ$. Therefore, the given angle $2x + 10^\circ$ must be equal to $90^\circ$.

$$2x + 10 = 90$$

Subtract 10 from both sides of the equation.

$$2x = 90 - 10$$ $$2x = 80$$

Divide both sides by 2.

$$x = \frac{80}{2}$$ $$x = \boxed{40}$$