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Draw two perpendicular lines, label the angles A, B, C, D, describe their relationship, and solve for x if one angle is 2x+10 degrees.

Mathematics

ScanSolve AI Answer

Answer

1.4

40\text{40}

Step-by-step solution

3 steps

Part 1.1

To draw two perpendicular lines intersecting at a point O

Draw a straight horizontal line. Then, draw a straight vertical line that crosses the horizontal line exactly at its midpoint. The point where these two lines intersect is point O.

Part 1.2

To label the angles A, B, C, D formed around the intersection

Starting from the top-right quadrant and moving counter-clockwise, label the angles.

  • The angle in the top-right quadrant is A.
  • The angle in the top-left quadrant is B.
  • The angle in the bottom-left quadrant is C.
  • The angle in the bottom-right quadrant is D.

Part 1.3

The relationship between the angles

When two lines are perpendicular, they intersect to form four right angles.
Therefore, all four angles formed at the intersection are equal to 90∘90^\circ.

∠A=∠B=∠C=∠D=90∘\angle A = \angle B = \angle C = \angle D = 90^\circ

Additionally, vertically opposite angles are equal (∠A=∠C\angle A = \angle C and ∠B=∠D\angle B = \angle D), and adjacent angles on a straight line are supplementary (e.g., ∠A+∠B=180∘\angle A + \angle B = 180^\circ).

Part 1.4

40\text{40}

Solve for xx if one angle is given as 2x+10∘2x + 10^\circ and a perpendicular angle is 90∘90^\circ.

  1. Set up the equation.

    Since the angle is a perpendicular angle, its measure is 90∘90^\circ.

    2x+10∘=90∘2x + 10^\circ = 90^\circ
  2. Subtract 10∘10^\circ from both sides of the equation.

    2x=90∘−10∘2x = 90^\circ - 10^\circ 2x=80∘2x = 80^\circ
  3. Divide by 2 to solve for xx.

    x=80∘2x = \frac{80^\circ}{2} x=40∘x = 40^\circ

    The value of xx is 40\boxed{\text{40}}.

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