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Solve for x in terms of y: 3x = (6+y2)2 + x

Mathematics

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Answer

x=(6+y2)22x = \frac{(6+y^2)^2}{2}

Step-by-step solution

3 steps

  1. Write down the given equation.

    3x=(6+y2)2+x3x = (6+y^2)^2 + x

  2. Subtract xx from both sides of the equation to group terms with xx.

    3x−x=(6+y2)23x - x = (6+y^2)^2 2x=(6+y2)22x = (6+y^2)^2

  3. Divide both sides by 2 to solve for xx in terms of yy.

    x=(6+y2)22x = \frac{(6+y^2)^2}{2}

    The solution for xx in terms of yy is:

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