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What force is required to stretched a steel wire of cross sectional area 1 cm² to double its length (Y=2×10¹¹ Nm⁻²)?

Physics

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Q20

Step 1: The formula for the angle of minimum deviation δm\delta_m for a prism is

δm=(μ−1)A\delta_m = (\mu - 1) A

where μ\mu is the refractive index of the prism material and AA is the prism angle.

Step 2: Given A=60∘A = 60^\circ and δm=40∘\delta_m = 40^\circ, substitute the values.

40∘=(μ−1)×60∘40^\circ = (\mu - 1) \times 60^\circ

Step 3: Solve for μ−1\mu - 1.

μ−1=40∘60∘=23\mu - 1 = \frac{40^\circ}{60^\circ} = \frac{2}{3}

Step 4: Find μ\mu.

μ=1+23=53\mu = 1 + \frac{2}{3} = \frac{5}{3}

\dfrac{5}{3}

Q22

Step 1: Coulomb's law for the electrostatic force FF between two point charges qq separated by distance rr in vacuum is

F=kq2r2F = k \frac{q^2}{r^2}

where k=9×109 N⋅m2/C2k = 9 \times 10^9 \, \mathrm{N \cdot m^2 / C^2}.

Step 2: Given F=10 NF = 10 \, \mathrm{N}, r=2 mr = 2 \, \mathrm{m}, substitute the values.

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