This physics problem tests your understanding of fundamental physical laws and their applications. The step-by-step solution below breaks down the problem using relevant equations and physical reasoning.
What force is required to stretched a steel wire of cross sectional area 1 cm² to double its length (Y=2×10¹¹ Nm⁻²)?
Physics

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Answer
\dfrac{5}{3}
Q20
Step 1: The formula for the angle of minimum deviation for a prism is
where is the refractive index of the prism material and is the prism angle.
Step 2: Given and , substitute the values.
Step 3: Solve for .
Step 4: Find .
\dfrac{5{3}}
Q22
Step 1: Coulomb's law for the electrostatic force between two point charges separated by distance in vacuum is
where .
Step 2: Given , , substitute the values.
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Q20 Step 1: The formula for the angle of minimum deviation _m for a prism is _m = ( - 1) A where is the refractive index of the prism material and A is the prism angle.
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Q20 Step 1: The formula for the angle of minimum deviation _m for a prism is _m = ( - 1) A where is the refractive index of the prism material and A is the prism angle. Step 2: Given A = 60^ and _m = 40^, substitute the values. 40^ = ( - 1) × 60^ Step 3: Solve for - 1. 1 = (40^)/(60^) = (2)/(3) Step 4: Find . = 1 + (2)/(3) = (5)/(3) (5)/(3) Q22 Step 1: Coulomb's law for the electrostatic force F between two point charges q separated by distance r in vacuum is F = k (q^2)/(r^2) where k = 9 × 10^9 \, N · m^2 / C^2. Step 2: Given F = 10 \, N, r = 2 \, m, substitute the values. 10 = (9 ×