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Calculate the future value of an investment using simple and compound interest formulas.

Mathematics

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Step-by-step solution

2 steps
  1. Solve part (c)(i).

    This question involves simple interest. The formula for simple interest is I=PRTI = PRT, where:

    • II is the total interest earned.
    • PP is the principal amount (initial investment).
    • RR is the annual interest rate (as a decimal).
    • TT is the time in years.

    Given:

    • P = \500$
    • R=1.7%=0.017R = 1.7\% = 0.017
    • T=10T = 10 years

    Substitute these values into the formula: I=$500×0.017×10I = \$500 \times 0.017 \times 10 I=$85I = \$85

  2. Solve part (c)(ii).

    This question involves compound interest, compounded daily. The formula for compound interest is A=P(1+rn)ntA = P(1 + \frac{r}{n})^{nt}, where:

    • AA is the final amount.
    • PP is the principal amount (initial investment).
    • rr is the annual interest rate (as a decimal).
    • nn is the number of times interest is compounded per year.
    • tt is the time in years.

    Given:

    • P = \200$
    • Daily interest rate =0.0035%= 0.0035\%
    • Time =1= 1 year =365= 365 days

    First, convert the daily interest rate to a decimal:
    Daily rate =0.0035%=0.0035100=0.000035= 0.0035\% = \frac{0.0035}{100} = 0.000035

    Since the interest is compounded daily, the number of compounding periods is n=365n = 365 (days in 1 year).
    The interest rate given is already a per-day rate, so we can use it directly in the compound interest formula where r/nr/n becomes the daily rate and ntnt becomes the total number of days.
    Let idayi_{day} be the daily interest rate.
    The formula simplifies to A=P(1+iday)number of daysA = P(1 + i_{day})^{\text{number of days}}.

    Substitute the values: A=$200(1+0.000035)365A = \$200 (1 + 0.000035)^{365} A=$200(1.000035)365A = \$200 (1.000035)^{365} Calculate the value inside the parenthesis:

    (1.000035)365≈1.01285(1.000035)^{365} \approx 1.01285

    Now, multiply by the principal: A=$200×1.01285A = \$200 \times 1.01285 A≈$202.57A \approx \$202.57

    c)

    i) The total interest earned is \boxed{\85}$.

    ii) The value of Ollie's investment at the end of 1 year is \boxed{\202.57}$.

    Just one more to go! Send it over.

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