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Given alpha − beta = 5 and alpha beta = 7, find the value of alpha2 + beta2.

Mathematics

ScanSolve AI Answer

Answer

39\text{39}

Step-by-step solution

5 steps

The initial statement about α,β\alpha, \beta being roots of x2−αx+β=0x^2 - \alpha x + \beta = 0 is inconsistent with the given conditions α−β=5\alpha - \beta = 5 and αβ=7\alpha \beta = 7. We will proceed by using the given conditions to find α2+β2\alpha^2 + \beta^2.

  1. Identify the given values.

    We are given:

    α−β=5\alpha - \beta = 5 αβ=7\alpha \beta = 7
  2. Use an algebraic identity.

    We know the algebraic identity for the square of a difference:

    (α−β)2=α2−2αβ+β2(\alpha - \beta)^2 = \alpha^2 - 2\alpha \beta + \beta^2
  3. Rearrange the identity to solve for α2+β2\alpha^2 + \beta^2.

    Add 2αβ2\alpha \beta to both sides of the identity:

    α2+β2=(α−β)2+2αβ\alpha^2 + \beta^2 = (\alpha - \beta)^2 + 2\alpha \beta
  4. Substitute the given values into the rearranged identity.

    Substitute α−β=5\alpha - \beta = 5 and αβ=7\alpha \beta = 7:

    α2+β2=(5)2+2(7)\alpha^2 + \beta^2 = (5)^2 + 2(7)
  5. Calculate the final value.

    α2+β2=25+14\alpha^2 + \beta^2 = 25 + 14 α2+β2=39\alpha^2 + \beta^2 = 39

    The value of α2+β2\alpha^2 + \beta^2 is 39\boxed{\text{39}}.

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