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If alpha and beta are the roots of the equation 2x2 − 4x + 7 = 0, find alpha2 + beta2.

Mathematics

ScanSolve AI Answer

Answer

-3

Step-by-step solution

4 steps

If α\alpha and β\beta are the roots of the equation 2x2−4x+7=02x^2 - 4x + 7 = 0, find α2+β2\alpha^2 + \beta^2.

  1. Identify the coefficients.

    For the quadratic equation ax2+bx+c=0ax^2 + bx + c = 0, we have a=2a = 2, b=−4b = -4, c=7c = 7.

  2. Find the sum and product of the roots.

    Sum of roots: α+β=−ba\alpha + \beta = -\frac{b}{a}

    α+β=−−42=42=2\alpha + \beta = -\frac{-4}{2} = \frac{4}{2} = 2

    Product of roots: αβ=ca\alpha \beta = \frac{c}{a}

    αβ=72\alpha \beta = \frac{7}{2}
  3. Use the identity for α2+β2\alpha^2 + \beta^2.

    We know that α2+β2=(α+β)2−2αβ\alpha^2 + \beta^2 = (\alpha + \beta)^2 - 2\alpha \beta.

  4. Substitute the values of α+β\alpha + \beta and αβ\alpha \beta into the identity.

    α2+β2=(2)2−2(72)\alpha^2 + \beta^2 = (2)^2 - 2\left(\frac{7}{2}\right) α2+β2=4−7\alpha^2 + \beta^2 = 4 - 7 α2+β2=−3\alpha^2 + \beta^2 = -3

    The value of α2+β2\alpha^2 + \beta^2 is −3\boxed{-3}.

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