Given f(x) = 2x³ + ax² − 3x + 1 and the divisor is (x+1), so c = -1.

Step 1: Solve Question 1.
The remainder theorem states that if a polynomial $f(x)$ is divided by $(x-c)$, the remainder is $f(c)$.
Given $f(x) = 2x^3 + ax^2 - 3x + 1$ and the divisor is $(x+1)$, so $c = -1$.
The remainder is given as $-2$.
Therefore, $f(-1) = -2$.
Substitute $x=-1$ into $f(x)$:

$$f(-1) = 2(-1)^3 + a(-1)^2 - 3(-1) + 1$$ $$$$