Given LCM = 264, GCF = 4, and one number a = 30. We need to find the other number b.

Question

ScanSolve AI Tutor · Accepted Answer

Here's the solution for question 29, continuing from where we left off:

Substitute the given values into the formula.
We have the formula: $a \times b = \text{LCM}(a, b) \times \text{GCF}(a, b)$ .
Given $\text{LCM} = 264$ , $\text{GCF} = 4$ , and one number $a = 30$ . We need to find the other number $b$ .
$30 \times b = 264 \times 4$
Calculate the product of LCM and GCF.
$30b = 1056$
Solve for $b$ by dividing both sides by 30.
$b = \frac{1056}{30}$ $b = \frac{176}{5}$ $b = 35.2$
The other number is $\boxed{35.2}$ .

Here's the solution for question 30:
Break down the number 4,120,450,345 into periods (billions, millions, thousands, ones).
- Billions: 4
- Millions: 120
- Thousands: 450
- Ones: 345
Write the number in words based on the periods.
Four billion, one hundred twenty million, four hundred fifty thousand, three hundred forty-five.
Compare with the given options.
Option c) matches the breakdown.

The number 4,120,450,345 in words is c) $\boxed{\text{Four billion one hundred twenty million four hundred fifty thousand and three hundred forty five}}$ .

Here's the solution for question 31:
Break down the number 4,567,891 into periods (millions, thousands, ones).
- Millions: 4
- Thousands: 567
- Ones: 891
Write the number in words based on the periods.
The number 4,567,891 in words is $\boxed{\text{Four million, five hundred sixty-seven thousand, eight hundred ninety-one}}$ .

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