Given: O is the centre of the circle. PWSR is a cyclic quadrilateral. PW || OS. P₁ = 36^.

Here's a step-by-step solution for Question 3 and Question 4.

Question 3

Given: O is the centre of the circle. PWSR is a cyclic quadrilateral. PW || OS. $\hat{P}_1 = 36^\circ$.

3.1 Calculate $\hat{SOW}$

• Step 1: Identify parallel lines and transversal. Given PW || OS. Consider WO as a transversal.
• Step 2: Apply alternate interior angles theorem. $\angle PWO = \angle WOS$ (Alternate interior angles, PW || OS). So, $\hat{W}_1 = \hat{SOW}$.
• **Step 3: Analyze $\triangle OWS