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Given RST = x − 8^, the measure of arc RT is:

Mathematics

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Answer

53.6\text{53.6}

Step-by-step solution

4 steps
  1. Identify the relationship between the given angles and their intercepted arcs.

    The angle ∠RST\angle RST is a central angle that intercepts arc RT. Therefore, the measure of arc RT is equal to the measure of ∠RST\angle RST.
    The angle ∠PQR\angle PQR is an inscribed angle that intercepts arc PR. Therefore, the measure of arc PR is twice the measure of ∠PQR\angle PQR.

  2. Express the measures of the arcs in terms of xx.

    Given ∠RST=x−8∘\angle RST = x - 8^\circ, the measure of arc RT is:

    arc RT=(x−8)∘\text{arc RT} = (x - 8)^\circ

    Given ∠PQR=2x−40∘\angle PQR = 2x - 40^\circ, the measure of arc PR is:

    arc PR=2×(2x−40)∘=(4x−80)∘\text{arc PR} = 2 \times (2x - 40)^\circ = (4x - 80)^\circ
  3. Use the property that PT is a diameter.

    Since PT is a diameter, it divides the circle into two semicircles. The arc PRT is a semicircle, which means its total measure is 180∘180^\circ. Arc PRT is the sum of arc PR and arc RT.

    arc PR+arc RT=180∘\text{arc PR} + \text{arc RT} = 180^\circ
  4. Set up and solve the equation for xx.

    Substitute the expressions for arc PR and arc RT into the equation from Step 3:

    (4x−80)+(x−8)=180(4x - 80) + (x - 8) = 180

    Combine like terms:

    5x−88=1805x - 88 = 180

    Add 88 to both sides of the equation:

    5x=180+885x = 180 + 88 5x=2685x = 268

    Divide by 5 to find the value of xx:

    x=2685x = \frac{268}{5} x=53.6x = 53.6

    The value of xx is 53.6\boxed{\text{53.6}}.

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