This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.

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Answer
{1, 2, 3, 4, 5, 6}
Step 1: Solve Question 1. Given the sets:
a) Find The union of two sets includes all elements present in either set. b) Find The intersection of two sets includes only the elements common to both sets. c) Find First, calculate . From part (a), . Next, find the intersection of this result with . The answers for Question 1 are: *a) *b) *c)
Step 2: Solve Question 2. Given: Total students = 50 Students who like Mathematics () = 30 Students who like Physics () = 20 Students who like both Mathematics and Physics () = 10
a) How many students like only Mathematics? To find students who like only Mathematics, subtract those who like both from the total who like Mathematics. b) How many students like only Physics? To find students who like only Physics, subtract those who like both from the total who like Physics. The answers for Question 2 are: *a) *b)
Step 3: Solve Question 3. Given the universal set and sets and : (reordered from the original list) (reordered from the original list) (reordered from the original list)
a) Find (complement of A) The complement of A contains all elements in that are not in . b) Find (complement of N) The complement of N contains all elements in that are not in . c) Find Assuming "B" is a typo and refers to set from the problem statement, we will calculate . First, find . Next, find the complement of . The answers for Question 3 are: *a) *b) *c) (assuming B refers to N)
Step 4: Solve Question 4. Given the sets:
a) Find (set difference between A and M) The set difference contains elements that are in A but not in M. b) Find (set difference between M and A) The set difference contains elements that are in M but not in A.
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Solve Question 1. Given the sets: H = \1, 2, 3, 4\ B = \3, 4, 5, 6\ Q = \2, 4, 6, 8\ a) Find H B The union of two sets includes all elements present in either set.
This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.