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Given side ratio (smaller to larger) is 4:5.

Mathematics

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3 parts
a

154 cm2\text{}154 \text{ cm}^2\text{}

b

113.14 cm2 (approx.) or 7927 cm2\text{}113.14 \text{ cm}^2 \text{ (approx.) or } \frac{792}{7} \text{ cm}^2\text{}

c

78.57 cm2 (approx.) or 5507 cm2\text{}78.57 \text{ cm}^2 \text{ (approx.) or } \frac{550}{7} \text{ cm}^2\text{}

454.55 (approx.) or 500011\text{}454.55 \text{ (approx.) or } \frac{5000}{11}\text{}

Step-by-step solution

12 steps

Here are the solutions to the problems:

24. Two triangles are similar with sides in the ratio 4:5. If the area of the smaller triangle is 64 cm264 \text{ cm}^2, find the area of the larger triangle.

Step 1: Understand the relationship between the ratio of sides and the ratio of areas for similar figures.
If the ratio of corresponding sides of two similar triangles is a:ba:b, then the ratio of their areas is a2:b2a^2:b^2.
Given side ratio (smaller to larger) is 4:54:5.
So, the area ratio (smaller to larger) is 42:52=16:254^2:5^2 = 16:25.

Step 2: Set up a proportion using the area ratio and the given area.
Let AsA_s be the area of the smaller triangle and AlA_l be the area of the larger triangle.

AsAl=1625\frac{A_s}{A_l} = \frac{16}{25}

Given As=64 cm2A_s = 64 \text{ cm}^2.

64 cm2Al=1625\frac{64 \text{ cm}^2}{A_l} = \frac{16}{25}

Step 3: Solve for AlA_l.

16×Al=64 cm2×2516 \times A_l = 64 \text{ cm}^2 \times 25 Al=64×2516 cm2A_l = \frac{64 \times 25}{16} \text{ cm}^2 Al=4×25 cm2A_l = 4 \times 25 \text{ cm}^2 Al=100 cm2A_l = \boxed{\text{}100 \text{ cm}^2\text{}}

25. Define the term Circle and state the relationship between radius and diameter.
A circle is a set of all points in a plane that are equidistant from a fixed central point.
The relationship between radius (rr) and diameter (dd) is that the diameter is twice the radius, or d=2rd = 2r.

26. Find the circumference of a circle with a radius of 7 cm7 \text{ cm}. (π=227\pi = \frac{22}{7})

Step 1: Use the formula for the circumference of a circle.

C=2πrC = 2\pi r

Step 2: Substitute the given values r=7 cmr = 7 \text{ cm} and π=227\pi = \frac{22}{7}.

C=2×227×7 cmC = 2 \times \frac{22}{7} \times 7 \text{ cm} C=2×22 cmC = 2 \times 22 \text{ cm} C=44 cmC = \boxed{\text{}44 \text{ cm}\text{}}

27. Calculate the area of the following use π=227\pi = \frac{22}{7}

Part a· 3 steps

Circle with diameter 14cm

  1. Find the radius.

    r=diameter2=14 cm2=7 cmr = \frac{\text{diameter}}{2} = \frac{14 \text{ cm}}{2} = 7 \text{ cm}
  2. Use the formula for the area of a circle.

    A=πr2A = \pi r^2
  3. Substitute the values.

    A=227×(7 cm)2A = \frac{22}{7} \times (7 \text{ cm})^2 A=227×49 cm2A = \frac{22}{7} \times 49 \text{ cm}^2 A=22×7 cm2A = 22 \times 7 \text{ cm}^2 A=154 cm2A = \boxed{\text{}154 \text{ cm}^2\text{}}

Part b

113.14 cm2 (approx.) or 7927 cm2\text{}113.14 \text{ cm}^2 \text{ (approx.) or } \frac{792}{7} \text{ cm}^2\text{}

Circle with diameter 12cm

  1. Find the radius.

    r=diameter2=12 cm2=6 cmr = \frac{\text{diameter}}{2} = \frac{12 \text{ cm}}{2} = 6 \text{ cm}
  2. Use the formula for the area of a circle.

    A=πr2A = \pi r^2
  3. Substitute the values.

    A=227×(6 cm)2A = \frac{22}{7} \times (6 \text{ cm})^2 A=227×36 cm2A = \frac{22}{7} \times 36 \text{ cm}^2 A=7927 cm2A = \frac{792}{7} \text{ cm}^2 A=113.14 cm2 (approx.) or 7927 cm2A = \boxed{\text{}113.14 \text{ cm}^2 \text{ (approx.) or } \frac{792}{7} \text{ cm}^2\text{}}

Part c

78.57 cm2 (approx.) or 5507 cm2\text{}78.57 \text{ cm}^2 \text{ (approx.) or } \frac{550}{7} \text{ cm}^2\text{}

Quarter circle with radius 10cm

  1. Identify the radius.

    r=10 cmr = 10 \text{ cm}
  2. Use the formula for the area of a quarter circle.

    A=14πr2A = \frac{1}{4} \pi r^2
  3. Substitute the values.

    A=14×227×(10 cm)2A = \frac{1}{4} \times \frac{22}{7} \times (10 \text{ cm})^2 A=14×227×100 cm2A = \frac{1}{4} \times \frac{22}{7} \times 100 \text{ cm}^2 A=220028 cm2A = \frac{2200}{28} \text{ cm}^2 A=5507 cm2A = \frac{550}{7} \text{ cm}^2 A=78.57 cm2 (approx.) or 5507 cm2A = \boxed{\text{}78.57 \text{ cm}^2 \text{ (approx.) or } \frac{550}{7} \text{ cm}^2\text{}}

    28. The wheel of a bicycle has a radius of 35 cm35 \text{ cm}. How many revolutions will it make in covering 1 km1 \text{ km}?

  4. Calculate the circumference of the wheel.

    C=2πrC = 2\pi r

    Using π=227\pi = \frac{22}{7} and r=35 cmr = 35 \text{ cm}:

    C=2×227×35 cmC = 2 \times \frac{22}{7} \times 35 \text{ cm} C=2×22×5 cmC = 2 \times 22 \times 5 \text{ cm} C=220 cmC = 220 \text{ cm}
  5. Convert the total distance to centimeters.

    1 km=1000 m1 \text{ km} = 1000 \text{ m} 1000 m=1000×100 cm=100000 cm1000 \text{ m} = 1000 \times 100 \text{ cm} = 100000 \text{ cm}
  6. Calculate the number of revolutions.

    Number of Revolutions=Total DistanceCircumference\text{Number of Revolutions} = \frac{\text{Total Distance}}{\text{Circumference}} Number of Revolutions=100000 cm220 cm\text{Number of Revolutions} = \frac{100000 \text{ cm}}{220 \text{ cm}} Number of Revolutions=1000022\text{Number of Revolutions} = \frac{10000}{22} Number of Revolutions=500011\text{Number of Revolutions} = \frac{5000}{11} Number of Revolutions=454.55 (approx.) or 500011\text{Number of Revolutions} = \boxed{\text{}454.55 \text{ (approx.) or } \frac{5000}{11}\text{}}

    Since revolutions must be whole numbers for full rotations, the wheel makes 454 full revolutions.

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