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Given Tan A = 3. Find the value of Sin A, Cos A, Sec A, Cosec A, and Cot A (in surd form).

Mathematics

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It seems you have provided a new set of questions. Since there is no question numbered "7" in the image you just sent, I will solve the first question in Section B, which is question 1.

SECTION B: THEORY

1. Given Tan A = 3. Find the value of:

(i) Sin A

(ii) Cos A

(iii) Sec A

(iv) Cosec A

(v) Cot A
(In Surd form)

  1. Use the definition of tan⁡A\tan A.

    Given tan⁡A=3\tan A = 3. In a right-angled triangle, tan⁡A=OppositeAdjacent\tan A = \frac{\text{Opposite}}{\text{Adjacent}}.
    So, we can consider the Opposite side to be 3 units and the Adjacent side to be 1 unit.

  2. Calculate the Hypotenuse using the Pythagorean theorem.

    Hypotenuse2=Opposite2+Adjacent2\text{Hypotenuse}^2 = \text{Opposite}^2 + \text{Adjacent}^2 Hypotenuse2=32+12\text{Hypotenuse}^2 = 3^2 + 1^2 Hypotenuse2=9+1\text{Hypotenuse}^2 = 9 + 1 Hypotenuse2=10\text{Hypotenuse}^2 = 10 Hypotenuse=10\text{Hypotenuse} = \sqrt{10}
  3. Find the values of the trigonometric ratios.

    (i) Sin A

    sin⁡A=OppositeHypotenuse=310\sin A = \frac{\text{Opposite}}{\text{Hypotenuse}} = \frac{3}{\sqrt{10}}

    Rationalize the denominator:

    sin⁡A=310×1010=31010\sin A = \frac{3}{\sqrt{10}} \times \frac{\sqrt{10}}{\sqrt{10}} = \frac{3\sqrt{10}}{10}

    The final answer for Sin A is 31010\boxed{\frac{3\sqrt{10}}{10}}.

    (ii) Cos A

    cos⁡A=AdjacentHypotenuse=110\cos A = \frac{\text{Adjacent}}{\text{Hypotenuse}} = \frac{1}{\sqrt{10}}

    Rationalize the denominator:

    cos⁡A=110×1010=1010\cos A = \frac{1}{\sqrt{10}} \times \frac{\sqrt{10}}{\sqrt{10}} = \frac{\sqrt{10}}{10}

    The final answer for Cos A is 1010\boxed{\frac{\sqrt{10}}{10}}.

    (iii) Sec A

    sec⁡A=1cos⁡A=HypotenuseAdjacent=101\sec A = \frac{1}{\cos A} = \frac{\text{Hypotenuse}}{\text{Adjacent}} = \frac{\sqrt{10}}{1} sec⁡A=10\sec A = \sqrt{10}

    The final answer for Sec A is 10\boxed{\sqrt{10}}.

    (iv) Cosec A

    csc⁡A=1sin⁡A=HypotenuseOpposite=103\csc A = \frac{1}{\sin A} = \frac{\text{Hypotenuse}}{\text{Opposite}} = \frac{\sqrt{10}}{3}

    The final answer for Cosec A is 103\boxed{\frac{\sqrt{10}}{3}}.

    (v) Cot A

    cot⁡A=1tan⁡A=AdjacentOpposite=13\cot A = \frac{1}{\tan A} = \frac{\text{Adjacent}}{\text{Opposite}} = \frac{1}{3}

    The final answer for Cot A is 13\boxed{\frac{1}{3}}.

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