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Given that a = -2, b = -1 and c = 3, evaluate; 2(a + c)2 - (a - b) 3(a + b)

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2 parts
15

40 cubes40 \text{ cubes}

16

−13-\frac{1}{3}

Step-by-step solution

7 steps

Part 15· 3 steps

Kizuizi cha mbao chenye vipimo vya 24cm kwa 48cm kwa 60cm kinakatwa kuwa idadi ndogo zaidi ya cubes zinazopatikana.

  1. Tafuta urefu wa upande wa cube kubwa zaidi.

    Ili kupata idadi ndogo zaidi ya cubes, kila cube lazima iwe kubwa iwezekanavyo. Hii inamaanisha urefu wa upande wa cube lazima uwe kigawanyo kikubwa zaidi cha kawaida (GCD) cha vipimo vya kizuizi cha mbao.
    Vipimo ni 24 cm, 48 cm, na 60 cm.
    Tunatafuta GCD(24, 48, 60).
    Vigawanyo vya 24: 1, 2, 3, 4, 6, 8, 12, 24
    Vigawanyo vya 48: 1, 2, 3, 4, 6, 8, 12, 16, 24, 48
    Vigawanyo vya 60: 1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30, 60
    Kigawanyo kikubwa zaidi cha kawaida ni 12.
    Kwa hivyo, urefu wa upande wa kila cube, ss, ni 12 cm.

  2. Kokotoa idadi ya cubes kwa kila mwelekeo.

    Idadi ya cubes kando ya urefu = 60 cm12 cm=5\frac{60 \text{ cm}}{12 \text{ cm}} = 5
    Idadi ya cubes kando ya upana = 48 cm12 cm=4\frac{48 \text{ cm}}{12 \text{ cm}} = 4
    Idadi ya cubes kando ya urefu = 24 cm12 cm=2\frac{24 \text{ cm}}{12 \text{ cm}} = 2

  3. Kokotoa jumla ya idadi ya cubes.

    Jumla ya idadi ya cubes = (Idadi ya urefu) ×\times (Idadi ya upana) ×\times (Idadi ya urefu)
    Jumla ya idadi ya cubes = 5×4×2=405 \times 4 \times 2 = 40.

    40 cubes\boxed{40 \text{ cubes}}

Part 16

−13-\frac{1}{3}

Kutokana na a=−2,b=−1a = -2, b = -1 na c=3c = 3, tathmini:

2(a+c)2−(a−b)3(a+b)\frac{2(a + c)^2 - (a - b)}{3(a + b)}
  1. Badilisha thamani za $a, b, c$ kwenye usemi.

    2((−2)+3)2−((−2)−(−1))3((−2)+(−1))\frac{2((-2) + 3)^2 - ((-2) - (-1))}{3((-2) + (-1))}
  2. Rahisisha nambari (numerator).

    Kwanza, hesabu ndani ya mabano:
    a+c=−2+3=1a + c = -2 + 3 = 1
    a−b=−2−(−1)=−2+1=−1a - b = -2 - (-1) = -2 + 1 = -1
    Sasa, badilisha hizi kwenye nambari:

    2(1)2−(−1)2(1)^2 - (-1) 2(1)−(−1)2(1) - (-1) 2+1=32 + 1 = 3

    Kwa hivyo, nambari ni 3.

  3. Rahisisha denomineta (denominator).

    Kwanza, hesabu ndani ya mabano:
    a+b=−2+(−1)=−2−1=−3a + b = -2 + (-1) = -2 - 1 = -3
    Sasa, badilisha hii kwenye denomineta:

    3(−3)=−93(-3) = -9

    Kwa hivyo, denomineta ni -9.

  4. Gawanya nambari kwa denomineta.

    3−9=−13\frac{3}{-9} = -\frac{1}{3} −13\boxed{-\frac{1}{3}}

    Kumbuka: Swali (b) "Determine his average speed" halina muktadha wa kutosha katika picha hii ili kutatuliwa.

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