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Given the equation 2x² − 3x + 1 = 0, we have a=2, b=-3, and c=1.

Mathematics

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11. If α\alpha and β\beta are roots of 2x2−3x+1=02x^2 - 3x + 1 = 0, find α/β+β/α\alpha/\beta + \beta/\alpha

Step 1: Find the sum and product of the roots for the given quadratic equation.
For a quadratic equation ax2+bx+c=0ax^2 + bx + c = 0, the sum of the roots is α+β=−ba\alpha + \beta = -\frac{b}{a} and the product of the roots is αβ=ca\alpha \beta = \frac{c}{a}.
Given the equation 2x2−3x+1=02x^2 - 3x + 1 = 0, we have a=2a=2, b=−3b=-3, and c=1c=1.
Sum of roots:

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