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Given that a + b = 9 and a2 + b2 = 71, find the value of (ab)3. (b) Factorise completely. x2 - x - 20 (c) T = 2pisqrt(l/g). Find T when l = 22.8 and g = 9.8. (d) Express as a single fraction in its simplest form. (a+2)/4 + (a+3)/5

Mathematics

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Answers

4 parts
a

125\text{125}

b

(x-5)(x+4)

c

9.58\text{9.58}

d

9a+2220\frac{9a+22}{20}

Step-by-step solution

12 steps

Part a· 3 steps

  1. Use the algebraic identity (a+b)2=a2+b2+2ab(a+b)^2 = a^2 + b^2 + 2ab.

    Substitute the given values a+b=9a+b=9 and a2+b2=71a^2+b^2=71 into the identity.

    (9)2=71+2ab(9)^2 = 71 + 2ab
  2. Solve for abab.

    81=71+2ab81 = 71 + 2ab 81−71=2ab81 - 71 = 2ab 10=2ab10 = 2ab ab=102ab = \frac{10}{2} ab=5ab = 5
  3. Calculate (ab)3(ab)^3.

    (ab)3=(5)3(ab)^3 = (5)^3 (ab)3=5×5×5(ab)^3 = 5 \times 5 \times 5 (ab)3=125(ab)^3 = 125

    The value of (ab)3(ab)^3 is 125\boxed{\text{125}}.

Part b(x-5)(x+4)

  1. To factorise x2−x−20x^2 - x - 20, find two numbers that multiply to -20 and add to -1.

    The numbers are -5 and 4.

  2. Write the expression in factored form.

    x2−x−20=(x−5)(x+4)x^2 - x - 20 = (x-5)(x+4)

    The factorised expression is (x−5)(x+4)\boxed{(x-5)(x+4)}.

Part c

9.58\text{9.58}

  1. Substitute l=22.8l = 22.8 and g=9.8g = 9.8 into the formula T=2πlgT = 2\pi\sqrt{\frac{l}{g}}.

    T=2π22.89.8T = 2\pi\sqrt{\frac{22.8}{9.8}}
  2. Calculate the value inside the square root.

    T=2π2.3265306...T = 2\pi\sqrt{2.3265306...}
  3. Calculate the square root and then multiply by 2π2\pi.

    T=2π×1.5252969...T = 2\pi \times 1.5252969... T=2×3.14159265...×1.5252969...T = 2 \times 3.14159265... \times 1.5252969... T=9.5839...T = 9.5839...

    Rounding to three significant figures:

    T≈9.58T \approx 9.58

    The value of TT is 9.58\boxed{\text{9.58}}.

Part d

9a+2220\frac{9a+22}{20}

  1. Find a common denominator for the fractions a+24\frac{a+2}{4} and a+35\frac{a+3}{5}.

    The least common multiple of 4 and 5 is 20.

  2. Rewrite each fraction with the common denominator.

    a+24=5(a+2)5×4=5a+1020\frac{a+2}{4} = \frac{5(a+2)}{5 \times 4} = \frac{5a+10}{20} a+35=4(a+3)4×5=4a+1220\frac{a+3}{5} = \frac{4(a+3)}{4 \times 5} = \frac{4a+12}{20}
  3. Add the two fractions.

    5a+1020+4a+1220=(5a+10)+(4a+12)20\frac{5a+10}{20} + \frac{4a+12}{20} = \frac{(5a+10) + (4a+12)}{20}
  4. Combine like terms in the numerator.

    5a+4a+10+1220=9a+2220\frac{5a+4a+10+12}{20} = \frac{9a+22}{20}

    The expression as a single fraction is 9a+2220\boxed{\frac{9a+22}{20}}.

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