Given that log2 a = 3, log2 b = -2,andlog2 c = 5, evaluate log2 8 sqrt(a5)bc2.

July 8, 2026Mathematics

ScanSolve AI Answer

July 8, 2026

Answer

13 years

Step 1: Calculate the sum of (age $\times$ frequency). $\sum (x \cdot f) = (12 \times 8) + (13 \times 10) + (14 \times 4) + (15 \times 2)$ $\sum (x \cdot f) = 96 + 130 + 56 + 30$ $\sum (x \cdot f) = 312$

Step 2: Calculate the sum of frequencies (total number of pupils). $\sum f = 8 + 10 + 4 + 2$ $\sum f = 24$

Step 3: Calculate the mean age using the formula $\text{Mean} = \frac{\sum (x \cdot f)}{\sum f}$ . $Mean = \frac{312}{24}$ $Mean = 13$

The mean age of the class is $\boxed{13 years}$ .

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f = 8 + 10 + 4 + 2 f = 24 Step 3: Calculate the mean age using the formula Mean = ( (x · f))/( f).
Mean = (312)/(24) Mean = 13 The mean age of the class is 13 years.
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Asked on July 8, 2026Mathematics

This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.

ScanSolve AI AnswerAnswered on July 8, 2026

Step 1: Calculate the sum of (age × frequency). (x · f) = (12 × 8) + (13 × 10) + (14 × 4) + (15 × 2) (x · f) = 96 + 130 + 56 + 30 (x · f) = 312 Step 2: Calculate the sum of frequencies (total number of pupils). f = 8 + 10 + 4 + 2 f = 24 Step 3: Calculate the mean age using the formula Mean = ( (x · f))/( f). Mean = (312)/(24) Mean = 13 The mean age of the class is 13 years. Send me the next one 📸