Given that log2 a = 3, log2 b = −2,andlog2 c = 5, evaluate log2 8 sqrt(a5)bc².

Step 1: Calculate the sum of (age × frequency). ∑ (x · f) = (12 × 8) + (13 × 10) + (14 × 4) + (15 × 2); ∑ (x · f) = 96 + 130 + 56 + 30; ∑ (x · f) = 312 Step 2: Calculate the sum of frequencies (total number of pupils). ∑ f = 8 + 10 + 4 + 2; ∑ f = 24; Step 3: Calculate the mean age using the formula Mean = (∑ (x · f))/(∑ f). Mean = 312/24; Mean = 13 The mean age of the class is 13 years.

Given that log2 a = 3, log2 b = −2,andlog2 c = 5, evaluate log2 8 sqrt(a5)bc².

Step 1: Calculate the sum of (age × frequency). ∑ (x · f) = (12 × 8) + (13 × 10) + (14 × 4) + (15 × 2); ∑ (x · f) = 96 + 130 + 56 + 30; ∑ (x · f) = 312 Step 2: Calculate the sum of frequencies (total number of pupils). ∑ f = 8 + 10 + 4 + 2; ∑ f = 24; Step 3: Calculate the mean age using the formula Mean = (∑ (x · f))/(∑ f). Mean = 312/24; Mean = 13 The mean age of the class is 13 years.

Solved: Given that log2 a = 3, log2 b = −2,andlog2 c = 5…

Calculate the sum of (age $\times$ frequency).
$\sum (x \cdot f) = (12 \times 8) + (13 \times 10) + (14 \times 4) + (15 \times 2)$ $\sum (x \cdot f) = 96 + 130 + 56 + 30$ $\sum (x \cdot f) = 312$
Calculate the sum of frequencies (total number of pupils).
$\sum f = 8 + 10 + 4 + 2$ $\sum f = 24$
Calculate the mean age using the formula $\text{Mean} = \frac{\sum (x \cdot f)}{\sum f}$ .
$\text{Mean} = \frac{312}{24}$ $\text{Mean} = 13$
The mean age of the class is $\text{13 years}$ .

Given that log2 a = 3, log2 b = -2,andlog2 c = 5, evaluate log2 8 sqrt(a5)bc².

Answer

Step-by-step solution

Calculate the sum of (age $\times$ frequency).

Calculate the sum of frequencies (total number of pupils).

Calculate the mean age using the formula $\text{Mean} = \frac{\sum (x \cdot f)}{\sum f}$ .

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