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Given that P = 2i − 7j and Q = -5i - 9j and 2P − 3Q + r = 0, find |r|.

Mathematics

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Q6) Given that P=2i−7j\mathbf{P} = 2\mathbf{i} - 7\mathbf{j} and Q=−5i−9j\mathbf{Q} = -5\mathbf{i} - 9\mathbf{j} and 2P−3Q+r=02\mathbf{P} - 3\mathbf{Q} + \mathbf{r} = 0, find ∣r∣|\mathbf{r}|.

Step 1: Express r\mathbf{r} in terms of P\mathbf{P} and Q\mathbf{Q}.
Given the equation 2P−3Q+r=02\mathbf{P} - 3\mathbf{Q} + \mathbf{r} = 0, we can rearrange it to solve for r\mathbf{r}:

r=−2P+3Q\mathbf{r} = -2\mathbf{P} + 3\mathbf{Q}

Step 2: Substitute the given vectors P\mathbf{P} and Q\mathbf{Q} into the expression for r\mathbf{r}.

r=−2(2i−7j)+3(−5i−9j)\mathbf{r} = -2(2\mathbf{i} - 7\mathbf{j}) + 3(-5\mathbf{i} - 9\mathbf{j}) r=(−4i+14j)+(−15i−27j)\mathbf{r} = (-4\mathbf{i} + 14\mathbf{j}) + (-15\mathbf{i} - 27\mathbf{j})

Step 3: Combine the i\mathbf{i} and j\mathbf{j} components to find r\mathbf{r}.

r=(−4−15)i+(14−27)j\mathbf{r} = (-4 - 15)\mathbf{i} + (14 - 27)\mathbf{j} r=−19i−13j\mathbf{r} = -19\mathbf{i} - 13\mathbf{j}

Step 4: Calculate the magnitude of r\mathbf{r}.
The magnitude of a vector ai+bja\mathbf{i} + b\mathbf{j} is given by a2+b2\sqrt{a^2 + b^2}.

∣r∣=(−19)2+(−13)2|\mathbf{r}| = \sqrt{(-19)^2 + (-13)^2} ∣r∣=361+169|\mathbf{r}| = \sqrt{361 + 169} ∣r∣=530|\mathbf{r}| = \sqrt{530}

The magnitude of r\mathbf{r} is 530\boxed{\sqrt{530}}.

Q7) A body of mass 2.5 kg2.5 \text{ kg} is suspended by two inextensible strings XPXP and YPYP which are inclined at 40∘40^\circ and 50∘50^\circ respectively to the downward vertical. Find the tension in both strings. (Take g=10 ms−2g = 10 \text{ ms}^{-2})

Step 1: Calculate the weight of the body.
The weight WW is the force due to gravity acting on the mass.

W=mgW = mg
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