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Given the system of linear equations ax + by = c and ax + by = 0, determine the number of solutions based on the value of c.

Mathematics

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Answer

If c≠0, there is no solution.\text{If } c \neq 0, \text{ there is no solution.}

If c=0, there are infinitely many solutions.\text{If } c = 0, \text{ there are infinitely many solutions.}

Step-by-step solution

3 steps

Here are the given equations:

ax+by=c(1)ax + by = c \quad (1) ax+by=0(2)ax + by = 0 \quad (2)
  1. Compare the equations.

    Both equations have the same coefficients for xx (aa) and yy (bb). This means they represent lines with the same slope.

  2. Analyze the constant terms.

    The constant term in equation (1) is cc, and in equation (2) it is 0. The relationship between the two lines (and thus the number of solutions) depends on the value of cc.

  3. Determine the number of solutions.

    • Case 1: If c≠0c \neq 0 If cc is any non-zero number, then ax+byax + by cannot simultaneously equal cc and 0. This means the two equations represent two distinct parallel lines. Parallel lines never intersect, so there is no solution to the system.

    • Case 2: If c=0c = 0 If cc is equal to 0, then both equations become ax+by=0ax + by = 0. This means the two equations are identical. They represent the same line. In this case, there are infinitely many solutions, as any point (x,y)(x, y) that satisfies ax+by=0ax + by = 0 is a solution to the system.

    The number of solutions depends on the value of cc:

    If c≠0, there is no solution.\boxed{\text{If } c \neq 0, \text{ there is no solution.}} If c=0, there are infinitely many solutions.\boxed{\text{If } c = 0, \text{ there are infinitely many solutions.}}
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