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Given the volume of a pyramid V = (1)/(3)xyh, we need to find the expression for x in terms of V, y, and h.

Mathematics

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2 parts
a

12.04 cm12.04 \text{ cm}

b

269.06∘269.06^\circ

Step-by-step solution

4 steps

Here are the solutions to your questions.

:
Given the volume of a pyramid V=13xyhV = \frac{1}{3}xyh, we need to find the expression for xx in terms of V,y,V, y, and hh.

Step 1: Write the given formula.

V=13xyhV = \frac{1}{3}xyh

Step 2: Multiply both sides by 3 to eliminate the fraction.

3V=xyh3V = xyh

Step 3: Divide both sides by yhyh to isolate xx.

x=3Vyhx = \frac{3V}{yh}

The expression for xx is 3Vyh\boxed{\frac{3V}{yh}}.

:
A right cone with base diameter 18 cm and perpendicular height 8 cm is made to form a sector of a circle.

Step 1: Determine the base radius of the cone.
The base diameter is 18 cm, so the base radius rr is half of the diameter.

r=182=9 cmr = \frac{18}{2} = 9 \text{ cm}

The perpendicular height hh is 8 cm.

Part a· 1 step

Calculate the Radius of the Sector

  1. The radius of the sector is equal to the slant height (LL) of the cone.

    Use the Pythagorean theorem to find the slant height.

    L=r2+h2L = \sqrt{r^2 + h^2} L=92+82L = \sqrt{9^2 + 8^2} L=81+64L = \sqrt{81 + 64} L=145 cmL = \sqrt{145} \text{ cm} L≈12.04 cmL \approx 12.04 \text{ cm}

    The radius of the sector is 12.04 cm\boxed{12.04 \text{ cm}}.

Part b

269.06∘269.06^\circ

Calculate the Angle of the Sector

  1. The arc length of the sector is equal to the circumference of the cone's base.

    C=2πrC = 2\pi r C=2π(9)C = 2\pi (9) C=18π cmC = 18\pi \text{ cm}
  2. Use the arc length formula S=RθS = R\theta, where SS is the arc length (18π18\pi), RR is the radius of the sector (145\sqrt{145}), and θ\theta is the angle in radians.

    18π=145θ18\pi = \sqrt{145} \theta θ=18π145 radians\theta = \frac{18\pi}{\sqrt{145}} \text{ radians}
  3. Convert the angle from radians to degrees.

    θdegrees=18π145×180∘π\theta_{degrees} = \frac{18\pi}{\sqrt{145}} \times \frac{180^\circ}{\pi} θdegrees=18×180∘145\theta_{degrees} = \frac{18 \times 180^\circ}{\sqrt{145}} θdegrees=3240∘145\theta_{degrees} = \frac{3240^\circ}{\sqrt{145}} θdegrees≈3240∘12.04159\theta_{degrees} \approx \frac{3240^\circ}{12.04159} θdegrees≈269.06∘\theta_{degrees} \approx 269.06^\circ

    The angle of the sector is approximately 269.06∘\boxed{269.06^\circ}.

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