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Given XPY = 47^.

Mathematics

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Answer

B. 86∘\text{B. } 86^\circ

Step-by-step solution

3 steps
  1. Find the angle subtended by arc XYXY at the center OO.

    The angle at the center is twice the angle at the circumference subtended by the same arc.
    Given ∠XPY=47∘\angle XPY = 47^\circ.

    ∠XOY=2×∠XPY\angle XOY = 2 \times \angle XPY ∠XOY=2×47∘=94∘\angle XOY = 2 \times 47^\circ = 94^\circ
  2. Identify the angles formed by the tangents and radii.

    A radius drawn to the point of tangency is perpendicular to the tangent.
    Therefore, ∠OXZ=90∘\angle OXZ = 90^\circ and ∠OYZ=90∘\angle OYZ = 90^\circ.

  3. Calculate ∠XZY\angle XZY using the sum of angles in quadrilateral OXZYOXZY.

    The sum of interior angles in a quadrilateral is 360∘360^\circ.
    In quadrilateral OXZYOXZY:

    ∠XOY+∠OXZ+∠OYZ+∠XZY=360∘\angle XOY + \angle OXZ + \angle OYZ + \angle XZY = 360^\circ

    Substitute the known angle values:

    94∘+90∘+90∘+∠XZY=360∘94^\circ + 90^\circ + 90^\circ + \angle XZY = 360^\circ 274∘+∠XZY=360∘274^\circ + \angle XZY = 360^\circ ∠XZY=360∘−274∘\angle XZY = 360^\circ - 274^\circ ∠XZY=86∘\angle XZY = 86^\circ

    The final answer is B. 86∘\text{B. } 86^\circ.

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