Find the gradient and y intercept of the following line 3y=5x−3

Mathematics

ScanSolve AI Answer

Answer

53\frac{5}{3}

-1
Graph of y = 5/3x − 1

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Key points of y = 5/3x − 1
Pointxy
y-intercept0−1
x-intercept0.60

Step-by-step solution

3 steps

Ili kupata mteremko (gradient) na sehemu ya kukata y (y-intercept) ya mstari, tunahitaji kuuweka mlinganyo katika mfumo wa y=mx+cy = mx + c, ambapo mm ni mteremko na cc ni sehemu ya kukata y.

  1. Panga upya mlinganyo 3y=5x−33y = 5x - 3 ili yy iwe peke yake upande mmoja.

    Gawanya pande zote mbili za mlinganyo kwa 3:

    3y3=5x3−33\frac{3y}{3} = \frac{5x}{3} - \frac{3}{3} y=53x−1y = \frac{5}{3}x - 1
  2. Tambua mteremko (gradient).

    Katika mfumo y=mx+cy = mx + c, mm ni mteremko. Kutoka mlinganyo wetu y=53x−1y = \frac{5}{3}x - 1, tunaona kwamba m=53m = \frac{5}{3}.
    Mteremko ni 53\boxed{\frac{5}{3}}.

  3. Tambua sehemu ya kukata y (y-intercept).

    Katika mfumo y=mx+cy = mx + c, cc ni sehemu ya kukata y. Kutoka mlinganyo wetu y=53x−1y = \frac{5}{3}x - 1, tunaona kwamba c=−1c = -1.
    Sehemu ya kukata y ni −1\boxed{-1}.

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