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Calculate the gradient (slope) m of the line.

Mathematics

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Okay, bazuunelson, let's re-solve question 14 for you.

14. (a) Find the equation of a line passing through $(2,3)$ and $(4,7)$

  1. Calculate the gradient (slope) mm of the line.

    The formula for the gradient is m=y2−y1x2−x1m = \frac{y_2 - y_1}{x_2 - x_1}.
    Using points (x1,y1)=(2,3)(x_1, y_1) = (2,3) and (x2,y2)=(4,7)(x_2, y_2) = (4,7):

    m=7−34−2=42=2m = \frac{7-3}{4-2} = \frac{4}{2} = 2
  2. Use the point-slope form of the equation of a line, y−y1=m(x−x1)y - y_1 = m(x - x_1).

    Using the point (2,3)(2,3) and m=2m=2:

    y−3=2(x−2)y - 3 = 2(x - 2)
  3. Simplify the equation to the slope-intercept form y=mx+cy=mx+c.

    y−3=2x−4y - 3 = 2x - 4 y=2x−4+3y = 2x - 4 + 3 y=2x−1y = 2x - 1

    The equation of the line is y=2x−1\boxed{y = 2x - 1}.

    14. (b) Find the midpoint of the line

  4. Recall the midpoint formula.

    For two points (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2), the midpoint MM is given by M=(x1+x22,y1+y22)M = \left(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2}\right).

  5. Substitute the given points $(2,3)$ and $(4,7)$ into the formula.

    M=(2+42,3+72)M = \left(\frac{2+4}{2}, \frac{3+7}{2}\right)
  6. Calculate the coordinates of the midpoint.

    M=(62,102)M = \left(\frac{6}{2}, \frac{10}{2}\right) M=(3,5)M = (3,5)

    The midpoint of the line is (3,5)\boxed{(3,5)}.

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