Step 2: Calculate the Range (continued from previous response) The minimum value in the dataset is $2.62$. The maximum value in the dataset is $3.57$. The range is the difference between the maximum and minimum values: $$\text{Range} = \text{Max} - \text{Min} = 3.57 - 2.62 = 0.95$$ The range is $\boxed{0.95}$. Step 3: Calculate the Standard Deviation ($s$) The formula for the sample standard deviation is: $$s = \sqrt{\frac{\sum (x_i - \bar{x})^2}{n-1}}$$ We have $n=7$ and $\bar{x} \approx 3.065714$. First, calculate the difference between each data point and the mean $(x_i - \bar{x})$ and square it $(x_i - \bar{x})^2$: • $2.75 - 3.065714 = -0.315714 \implies (-0.315714)^2 \approx 0.099675$ • $2.86 - 3.065714 = -0.205714 \implies (-0.205714)^2 \approx 0.042318$ • $3.57 - 3.065714 = 0.504286 \implies (0.504286)^2 \approx 0.254304$ • $2.62 - 3.065714 = -0.445714 \implies (-0.445714)^2 \approx 0.198661$ • $3.49 - 3.065714 = 0.424286 \implies (0.424286)^2 \approx 0.180018$ • $3.05 - 3.065714 = -0.015714 \implies (-0.015714)^2 \approx 0.000247$ • $3.12 - 3.065714 = 0.054286 \implies (0.054286)^2 \approx 0.002947$ Next, sum the squared differences: $$\sum (x_i - \bar{x})^2 \approx 0.099675 + 0.042318 + 0.254304 + 0.198661 + 0.180018 + 0.000247 + 0.002947 \approx 0.77817$$ Now, substitute this sum into the standard deviation formula: $$s = \sqrt{\frac{0.77817}{7-1}}$$ $$s = \sqrt{\frac{0.77817}{6}}$$ $$s = \sqrt{0.129695}$$ $$s \approx 0.3601319$$ Rounding to three decimal places: $$s \approx 0.360$$ The standard deviation is $\boxed{0.360}$.