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Find the HCF and LCM of 9, 6, and 8. Divide the LCM of 160, 18, 21

Mathematics

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: Find the HCF and LCM of 9p2q3r29p^2q^3r^2, 6p3q2r46p^3q^2r^4, and 8p2q4r38p^2q^4r^3.

  1. Find the prime factorization of the numerical coefficients and identify the powers of the variables.

    For 9p2q3r29p^2q^3r^2: 32⋅p2⋅q3⋅r23^2 \cdot p^2 \cdot q^3 \cdot r^2
    For 6p3q2r46p^3q^2r^4: 21⋅31⋅p3⋅q2⋅r42^1 \cdot 3^1 \cdot p^3 \cdot q^2 \cdot r^4
    For 8p2q4r38p^2q^4r^3: 23⋅p2⋅q4⋅r32^3 \cdot p^2 \cdot q^4 \cdot r^3

  2. Calculate the Highest Common Factor (HCF).

    The HCF is found by taking the lowest power of each common prime factor (numerical and variable) present in all expressions.

    • Numerical coefficients (9, 6, 8): There are no common prime factors other than 1. So, the HCF of the numerical coefficients is 1.
    • Variable pp: The lowest power is p2p^2.
    • Variable qq: The lowest power is q2q^2.
    • Variable rr: The lowest power is r2r^2.
    HCF=1⋅p2⋅q2⋅r2=p2q2r2\text{HCF} = 1 \cdot p^2 \cdot q^2 \cdot r^2 = p^2q^2r^2
  3. Calculate the Least Common Multiple (LCM).

    The LCM is found by taking the highest power of each prime factor (numerical and variable) present in any of the expressions.

    • Numerical coefficients (9, 6, 8): 9=329 = 3^2 6=2×36 = 2 \times 3 8=238 = 2^3 The highest power of 2 is 232^3. The highest power of 3 is 323^2. LCM of (9, 6, 8) =23×32=8×9=72= 2^3 \times 3^2 = 8 \times 9 = 72.
    • Variable pp: The highest power is p3p^3.
    • Variable qq: The highest power is q4q^4.
    • Variable rr: The highest power is r4r^4.
    LCM=72⋅p3⋅q4⋅r4=72p3q4r4\text{LCM} = 72 \cdot p^3 \cdot q^4 \cdot r^4 = 72p^3q^4r^4

    The HCF is p2q2r2\boxed{p^2q^2r^2} and the LCM is 72p3q4r4\boxed{72p^3q^4r^4}.

    : Find the LCM of 160,180,240160, 180, 240.
    (The question asks to "Divide the LCM", but does not specify by what. We will find the LCM.)

  4. Find the prime factorization of each number.

    160=16×10=24×(2×5)=25×51160 = 16 \times 10 = 2^4 \times (2 \times 5) = 2^5 \times 5^1 180=18×10=(2×32)×(2×5)=22×32×51180 = 18 \times 10 = (2 \times 3^2) \times (2 \times 5) = 2^2 \times 3^2 \times 5^1 240=24×10=(23×3)×(2×5)=24×31×51240 = 24 \times 10 = (2^3 \times 3) \times (2 \times 5) = 2^4 \times 3^1 \times 5^1
  5. Identify the highest power of each prime factor present in any of the numbers.

    • Highest power of 2: 252^5 (from 160)
    • Highest power of 3: 323^2 (from 180)
    • Highest power of 5: 515^1 (from 160, 180, 240)
  6. Multiply these highest powers to find the LCM.

    LCM=25×32×51\text{LCM} = 2^5 \times 3^2 \times 5^1 LCM=32×9×5\text{LCM} = 32 \times 9 \times 5 LCM=288×5\text{LCM} = 288 \times 5 LCM=1440\text{LCM} = 1440

    The LCM of 160,180,160, 180, and 240 is 1440\boxed{1440}.

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