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Find the HCF of the following. Leave the answers as prime factors. a 2×3×3×5; 2×2×3×3×3; 3×3×5×7

Mathematics

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5 parts
a

3×33 \times 3

b

2×32 \times 3

c

2×52 \times 5

d

2×3×32 \times 3 \times 3

e

3×5×73 \times 5 \times 7

Step-by-step solution

15 steps

To find the HCF (Highest Common Factor) of numbers given in prime factor form, we identify the common prime factors and take the lowest power of each common factor present in all the numbers.

Part a· 3 steps

The numbers are

N1=2×3×3×5N_1 = 2 \times 3 \times 3 \times 5
N2=2×2×3×3×3N_2 = 2 \times 2 \times 3 \times 3 \times 3
N3=3×3×5×7N_3 = 3 \times 3 \times 5 \times 7

  1. Identify common prime factors.

    The common prime factor is 3.

  2. Find the lowest power of the common prime factor.

    3 appears twice in N1N_1 (323^2), three times in N2N_2 (333^3), and twice in N3N_3 (323^2). The lowest power is 323^2.

  3. Multiply the common prime factors with their lowest powers.

    HCF=3×3\text{HCF} = 3 \times 3

    The HCF for a) is 3×3\boxed{3 \times 3}

Part b

2×32 \times 3

The numbers are

N1=2×2×3×5N_1 = 2 \times 2 \times 3 \times 5
N2=2×2×3×3×7N_2 = 2 \times 2 \times 3 \times 3 \times 7
N3=2×3×3×7N_3 = 2 \times 3 \times 3 \times 7

  1. Identify common prime factors.

    The common prime factors are 2 and 3.

  2. Find the lowest power of each common prime factor.

    For 2: 222^2 in N1N_1, 222^2 in N2N_2, 212^1 in N3N_3. The lowest power is 212^1.
    For 3: 313^1 in N1N_1, 323^2 in N2N_2, 323^2 in N3N_3. The lowest power is 313^1.

  3. Multiply the common prime factors with their lowest powers.

    HCF=2×3\text{HCF} = 2 \times 3

    The HCF for b) is 2×3\boxed{2 \times 3}

Part c

2×52 \times 5

The numbers are

N1=2×3×3×5N_1 = 2 \times 3 \times 3 \times 5
N2=2×2×2×5N_2 = 2 \times 2 \times 2 \times 5
N3=2×2×3×5×7N_3 = 2 \times 2 \times 3 \times 5 \times 7

  1. Identify common prime factors.

    The common prime factors are 2 and 5.

  2. Find the lowest power of each common prime factor.

    For 2: 212^1 in N1N_1, 232^3 in N2N_2, 222^2 in N3N_3. The lowest power is 212^1.
    For 5: 515^1 in N1N_1, 515^1 in N2N_2, 515^1 in N3N_3. The lowest power is 515^1.

  3. Multiply the common prime factors with their lowest powers.

    HCF=2×5\text{HCF} = 2 \times 5

    The HCF for c) is 2×5\boxed{2 \times 5}

Part d

2×3×32 \times 3 \times 3

The numbers are

N1=2×2×2×3×3×7N_1 = 2 \times 2 \times 2 \times 3 \times 3 \times 7
N2=2×2×3×3×3N_2 = 2 \times 2 \times 3 \times 3 \times 3
N3=2×3×3×3×7N_3 = 2 \times 3 \times 3 \times 3 \times 7

  1. Identify common prime factors.

    The common prime factors are 2 and 3.

  2. Find the lowest power of each common prime factor.

    For 2: 232^3 in N1N_1, 222^2 in N2N_2, 212^1 in N3N_3. The lowest power is 212^1.
    For 3: 323^2 in N1N_1, 333^3 in N2N_2, 333^3 in N3N_3. The lowest power is 323^2.

  3. Multiply the common prime factors with their lowest powers.

    HCF=2×3×3\text{HCF} = 2 \times 3 \times 3

    The HCF for d) is 2×3×3\boxed{2 \times 3 \times 3}

Part e

3×5×73 \times 5 \times 7

The numbers are

N1=2×3×3×5×7N_1 = 2 \times 3 \times 3 \times 5 \times 7
N2=3×5×5×7×7N_2 = 3 \times 5 \times 5 \times 7 \times 7
N3=2×2×3×5×5×7N_3 = 2 \times 2 \times 3 \times 5 \times 5 \times 7

  1. Identify common prime factors.

    The common prime factors are 3, 5, and 7.

  2. Find the lowest power of each common prime factor.

    For 3: 323^2 in N1N_1, 313^1 in N2N_2, 313^1 in N3N_3. The lowest power is 313^1.
    For 5: 515^1 in N1N_1, 525^2 in N2N_2, 525^2 in N3N_3. The lowest power is 515^1.
    For 7: 717^1 in N1N_1, 727^2 in N2N_2, 717^1 in N3N_3. The lowest power is 717^1.

  3. Multiply the common prime factors with their lowest powers.

    HCF=3×5×7\text{HCF} = 3 \times 5 \times 7

    The HCF for e) is 3×5×7\boxed{3 \times 5 \times 7}

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