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Can you help me find the factor pairs of 12 and 24? Also, I need help solving for missing numbers in multiplication equations.

Mathematics

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Here are the solutions for the problems:

Arrange 12 tiles
The ways to arrange 12 tiles are represented by the factor pairs of 12. Your work is correct.

  • 1×12=121 \times 12 = 12
  • 12×1=1212 \times 1 = 12
  • 2×6=122 \times 6 = 12
  • 6×2=126 \times 2 = 12
  • 3×4=123 \times 4 = 12
  • 4×3=124 \times 3 = 12

Arrange 24 tiles
To arrange 24 tiles, we find the factor pairs of 24.

  • 1×24=241 \times 24 = 24
  • 24×1=2424 \times 1 = 24
  • 2×12=242 \times 12 = 24
  • 12×2=2412 \times 2 = 24
  • 3×8=243 \times 8 = 24
  • 8×3=248 \times 3 = 24
  • 4×6=244 \times 6 = 24
  • 6×4=246 \times 4 = 24

I can multiply!

  1. Solve for the first missing number.

    12=2×?12 = 2 \times \boxed{?} 12÷2=612 \div 2 = 6

    So, 12=2×612 = 2 \times \boxed{6}.

  2. Solve for the second missing number.

    6=3×?6 = 3 \times \boxed{?} 6÷3=26 \div 3 = 2

    So, 6=3×26 = 3 \times \boxed{2}.

  3. Solve for the third missing number.

    3×?=123 \times \boxed{?} = 12 12÷3=412 \div 3 = 4

    So, 3×4=123 \times \boxed{4} = 12.

  4. Solve for the fourth missing number.

    ?×3=12\boxed{?} \times 3 = 12 12÷3=412 \div 3 = 4

    So, 4×3=12\boxed{4} \times 3 = 12.

  5. Solve for the fifth missing number.

    9=?×39 = \boxed{?} \times 3 9÷3=39 \div 3 = 3

    So, 9=3×39 = \boxed{3} \times 3.

  6. Solve for the sixth missing number.

    24=3×?24 = 3 \times \boxed{?} 24÷3=824 \div 3 = 8

    So, 24=3×824 = 3 \times \boxed{8}.

    Here are the completed equations:

    • 12=2×612 = 2 \times \boxed{\textbf{6}}
    • 6=3×26 = 3 \times \boxed{\textbf{2}}
    • 3×4=123 \times \boxed{\textbf{4}} = 12
    • 4×3=12\boxed{\textbf{4}} \times 3 = 12
    • 9=3×39 = \boxed{\textbf{3}} \times 3
    • 24=3×824 = 3 \times \boxed{\textbf{8}}
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